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Alisiya [41]
3 years ago
5

The figure in Quadrant III of the coordinate plane below is a transformation of the figure in quadrant II.

Mathematics
1 answer:
BARSIC [14]3 years ago
5 0

Answer: 2nd option, 3rd option, and the last option are all correct

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6279÷4= could you help me with this problem
Feliz [49]

Answer:  1,569.75

Step-by-step explanation:

6279÷4=1,569.75

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PLEASE HELP!!!!<br><br> Find the value of x.<br> 130 degrees<br> Xdegrees
strojnjashka [21]

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Step-by-step explanation:

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3 years ago
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A second particle, Q, also moves along the x-axis so that its velocity for 0 £ £t 4 is given by Q t cos 0.063 ( ) t 2 v t( ) = 4
Vladimir79 [104]

Answer:

The time interval when V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

The distance is 106.109 m

Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

V_Q(t) \geq 60    between   0 \leq t \leq 4

The schematic free body graphical representation of the above illustration was attached in the file below and the point when V_Q(t) \geq 60  is at 4 is obtained in the parabolic curve.

So, V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

Taking the integral of the time interval in order to determine the distance; we have:

distance = \int\limits^{3.519}_{1.866} {V_Q(t)} \, dt

= \int\limits^{3.519}_{1.866} {45\sqrt{t} cos(0.063 \ t^2)} \, dt

= By using the Scientific calculator notation;

distance = 106.109 m

4 0
3 years ago
Find the lowest common denominator.<br> 1/6 and 3/8<br> The lowest common denominator is
tiny-mole [99]

Answer:

24 as the denominator.

Step-by-step explanation:

6 goes into 24, 4 times.

8 goes into 24, 3 times.

7 0
4 years ago
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