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SOVA2 [1]
2 years ago
14

The best fitting straight line for a data set of X-values plotted against y-values is

Mathematics
1 answer:
densk [106]2 years ago
7 0

Answer:

a. a correlation matrix

Step-by-step explanation:

The best fitting straight line for a data set of X-values plotted against y-values is  called a correlation matrix.

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Martin is paid an hourly rate of d dollars per hour for the first 40 hours he works per week. He is paid one-and-a-half times hi
Nat2105 [25]

Answer:

40d + 10(1.5d) = 770 can be used to determine Martin's hourly pay.

Step-by-step explanation:

Given that:

Hourly rate = d

Earning to first 40 hours = 40d

Earning of more than 40 hours = 1.5d

Amount paid per week = $770

Hours worked = 50 hours

first 40 hours + 10 hours = total earned

40d + 10(1.5d) = 770

Hence,

40d + 10(1.5d) = 770 can be used to determine Martin's hourly pay.

5 0
2 years ago
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mixer [17]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
Pls help me guys! This is super hard
Mashcka [7]
I count 4 green stars and 6 red stars

ratio of green to red would be
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2:3
6 0
3 years ago
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Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior citizen tickets and 4 child ticke
FrozenT [24]

Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?

14S + 4C = 200

14S = 200 - 4C

S = (200 - 4C)/14

7S + 1C = 92

7S = 92 - C

S = (92 - C)/7

(200 - 4C)/14 = (92 - C)/7

7 x (200 - 4C) = 14 x (92 - C)

1400 - 28C = 1288 - 14C

1400 - 1288 = 28C - 14C

112 = 14C

C = 112/14 = 8

the price of one child ticket = $8

8 0
2 years ago
Which of the models represents cars as 37 1/2 of the total vehicles?
Aleonysh [2.5K]

Answer:from my understanding it should be D I would wait for someone else to answer just in case I’m wrong.

7 0
3 years ago
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