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tino4ka555 [31]
3 years ago
14

Phil is making a boat. His small model is 24 inches long and 4.75 inches wide. He is finalising it, and it is 8 feet long. How w

ide should his boat be?

Mathematics
1 answer:
Maslowich3 years ago
6 0

your answer would be 19 inches because 24 divided by 12(length of a foot in inches) is 2 and therefore you also divide 4.75 by 2 to get 2.375 and multiply that by 8 the amount of feet and your done

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How do you determine the domain of a function ?
Sunny_sXe [5.5K]

Answer:

Let y = f(x) be a function with an independent variable x and a dependent variable y.

If a function f provides a way to successfully produce a single value y using for that purpose a value for x then that

chosen x-value is said to belong to the domain of f. If there is a requirement that a y-value produced by a function

must be a real number, the following conditions are commonly checked:

1. Denominators cannot equal 0.

2. Radicands (expressions under a radical symbol) of even roots (square roots, etc)  

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2 years ago
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3 years ago
Two sets of equatic expressions are shown below in various forms: Line 1: x2 + 3x + 2 (x + 1)(x + 2) (x + 1.5)2 − 0.25 Line 2: x
kherson [118]

Answer:  The correct line is

\textup{Line 1 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25.

Step-by-step explanation:  We are given the following two sets of quadratic expressions in various forms:

\textup{Line 1: }x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25,\\\\\textup{Line 2 :}x^2+5x+6=(x+2)(x+3)=(x+2.5)^2+6.25.

We are to select one of the lines from above that represent three equivalent expressions.

We can see that there are three different forms of a quadratic expression in each of the lines:

First one is the simplified form, second is the factorised form and third one is the vertex form.

So, to check which line is correct, we need to calculate the factorised form and the vertex form from the simplified form.

We have

\textup{Line 1: }\\\\x^2+3x+2\\\\=x^2+2x+x+2\\\\=x(x+2)+1(x+2)\\\\=(x+1)(x+2),

and

x^2+3x+2\\\\=x^2+2\times x\times 1.5+(1.5)^2-(1.5)^2+2\\\\=(x+1.5)^2-2.25+2\\\\=(x+1.5)^2-0.25.

So,

\textup{Line 1 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25.

Thus, Line 1 contains three equivalent expressions.

Now,

\textup{Line 2: }\\\\x^2+5x+6\\\\=x^2+3x+2x+6\\\\=x(x+3)+2(x+3)\\\\=(x+2)(x+3),

and

x^2+5x+6\\\\=x^2+2\times x\times 2.5+(2.5)^2-(2.5)^2+6\\\\=(x+2.5)^2-6.25+6\\\\=(x+2.5)^2-0.25\neq (x+2.5)^2+6.25.

So,

\textup{Line 2 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2+6.25.

Thus, Line 2 does not contain three equivalent expressions.

Hence, Line 1 is correct.

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3 years ago
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otez555 [7]
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3 years ago
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Answer:

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3 years ago
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