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stiks02 [169]
3 years ago
6

Cathy buys 7 ounces of dried cherries in bulk. If dried

Mathematics
2 answers:
o-na [289]3 years ago
8 0

Answer:

A. $2.87

Step-by-step explanation:

Sholpan [36]3 years ago
5 0
A because it’s the answer
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What percent is five out of 12
Andru [333]

Answer:

41.66666

Step-by-step explanation:

4 0
4 years ago
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(07.05)
Llana [10]

Answer: n = -2

Step-by-step explanation:

3n +2(n + 2) = 9n + 12

(simplify 2(n + 2)) =

3n + 2n + 4 = 9n + 12

(subtract 9n from both sides)

3n + 2n - 9n + 4 = 12

-4n + 4 = 12

(subtract 4 from both sides)

-4n = 8

(divide -4 from both sides)

n = -2

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3 years ago
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The mean preparation fee H&R Block charged retail customers in 2012 was $183 (The Wall Street Journal, March 7, 2012). Use t
astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

z(p)=\frac{ME*\sqrt{N}}{s } where

  • Me is the margin of error from the mean
  • s is the standard deviation of the population
  • N is the sample size

a.

z(p)=\frac{8*\sqrt{30}}{50 } ≈ 0.8764

by looking z-table corresponding p value is 1-0.3808=0.6192

b.

z(p)=\frac{8*\sqrt{50}}{50 } ≈ 1.1314

by looking z-table corresponding p value is 1-0.2578=0.7422

c.

z(p)=\frac{8*\sqrt{100}}{50 } ≈ 1.6

by looking z-table corresponding p value is 1-0.1096=0.8904

d.

Minimum required sample size for 0.95 probability is

N≥(\frac{z*s}{ME} )^2 where

  • N is the sample size
  • z is the corresponding z-score in 95% probability (1.96)
  • s is the standard deviation (50)
  • ME is the margin of error (8)

then N≥(\frac{1.96*50}{8} )^2 ≈150.6

Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

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3 years ago
Help for number 12 pls
Marianna [84]
10 minutes left of homework
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Which graph represents the function<br><br> A<br> B<br> C<br> D
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