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creativ13 [48]
3 years ago
14

McKenzie and Cara both tried to find the missing side of the right triangle. Explain your reasoning. Please explain why one of t

hem is correct

Mathematics
2 answers:
Paladinen [302]3 years ago
7 0
By the Pythagorean Theorem:

h^2=x^2+y^2

Which just means that the hypotenuse (longest side) squared is equal to the sum of the side lengths squared...in this case:

h^2=5^2+13^2

h^2=25+169

h^2=194

h=√194

h≈13.93 in (to nearest hundredth of an inch)

Mckensey is correct as shown above.

Cara's mistake was in letting c be a side length instead of the length of the hypotenuse...
Andreas93 [3]3 years ago
3 0

Answer:

Cara's mistake was in letting c be a leg length instead of the length of the hypotenuse.

Step-by-step explanation:

chart shows documented error.

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What is A Ratio of 15 minutes:2 hours​
puteri [66]

Answer:

1:8

Step-by-step explanation:

soln,

In ,1hour= 60 mins

2hour= 2*60 mins = 120 mins.

now,

15/120( then divide 15 ones 15 and 15 * 8 is 120.) explanation

= 1/8

5 0
3 years ago
A square pyramid has a volume of 297 cubed feet. The width and length of the pyramid are
zalisa [80]

Answer:

11

Step-by-step explanation:

H =V/(LxW)/3

H = 297/(9x9)/3

H = 297/(81)/3

H = 297/27

H = 11

Therefore, the height of the pyramid is 11ft square

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3 years ago
1. X+4x+6x need help ASAP 10 minutes remaining ​
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3 years ago
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O<br> Decrease 40 by ratio of 4:5
Reika [66]

A decrease in the ratio 4:5 implies that :

New quantity:Old quantity = 4:5

Let the new quantity be \bf \: x

\bf∴ x : 40 = 4:5

=  > \bf \frac{x}{40}  =  \frac{4}{5}

\bf =  > 40 \times  \frac{x}{40}  = 40 \times  \frac{4}{5}

\bf =  > x = 8 \times 4

\bf =  > x = 32

So, the new quantity is 32

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3 years ago
Find the center of the circle whose equation is x² + y² = 4.
Varvara68 [4.7K]

Answer:

The center of circle is (0,0)

Step-by-step explanation:

We need to find the center of the circle of the equation x^{2}+y^{2}=4

Since, the general equation of circle is (x-h)^{2}+(y-k)^{2} = r^{2}

Where (h,k) is center of circle and r is radius.

Re-write the circle equation is x^{2}+y^{2}=4 as,

x^{2}+y^{2}=2^{2}

Compare x^{2}+y^{2}=2^{2} with (x-h)^{2}+(y-k)^{2} = r^{2}

so, (x-0)^{2}+(y-0)^{2} = 2^{2}

Hence, the center of circle is (0,0)

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3 years ago
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