Answer:
Her adjusted body weight is 78.26kg = 78.3kg, rounded to the nearest tenth.
Step-by-step explanation:
To find the Adjusted Body Weight(AjBW), first we have to consider the Ideal Body Weight(IBW).
We have the following formulas:
, in which i is the number of inches that the woman has above 5 feet.
, in which 
is her Actual Body Weight
So, in this problem:
Each pound has 0.45kg. So her weight is 
kg.
The woman is 8 inches above 5 feet, so 
.
kg
Her ideal body weight is 63.9kg. Her adjusted body weight is:
kg
Her adjusted body weight is 78.26kg = 78.3kg.
Answer:
29*sqrt(5)
Step-by-step explanation:
Start with sqrt (45). You must reduce it to it's prime factors.
45: 9 * 5 9 is not prime so reduce it.
45: 3 * 3 * 5
When you write √45, you should replace it with √(3*3*5)
The rule is
Rule: when you have a pair of equal prime factors under a root sign, you can take one out and throw one away.
Rule 2: If there are an odd number of equal primes one of them will be left underneath the root sign.
√45 = 3√5
11sqrt(45) - 4 sqrt(5) Substitute for 45
11*3*sqrt(5) - 4sqrt(5) Take out sqrt(5) using the distributive property.
(11*3 - 4)*sqrt(5) Combine 11 * 3
(33- 4) * sqrt(5) Do the subtraction
29 * sqrt(5) Answer
Answer:
The answer is 8
Step-by-step explanation:
2 + 6 = 8
make me brainliest
I think B not 100% sure though
