Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.

$\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill$

$\begin{cases} h=0\\ k=0\\ a=2\\ c=4 \end{cases}\implies \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{b^2} \\\\\\ c^2=a^2+b^2\implies 4^2=2^2+b^2\implies 16=4+b^2\implies \underline{12=b^2} \\\\\\ \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{12}\implies \boxed{\cfrac{x^2}{4}-\cfrac{y^2}{12}}$

5 0

2 years ago

500+2000+45+338+2145

Semenov [28]

Answer:

5,028

Step-by-step explanation:

7 0

2 years ago

What is the conjugate of -1-5i?

NARA [144]

Answer:

-6

Step-by-step explanation:

is -6

4 0

2 years ago

A triangle with an area of 37 units? is dilated by a scale factor of . Find the area of

sergeinik [125]

Answer:

<u>58 units</u>

Step-by-step explanation:

I decided that one side is 37 units and another is 2 units, since that would make the area 37 units. (you can also use 74 units and 1 unit)

Then I multiplied 37 by 5/4, which equals a new length of 46.25 units, and I also multiplied 2 by 5/4, which equals a new length of 2.5 units.

Finally, I solve for the area of the triangle:

1/2(46.25 x 2.5) ≈ <u>58 units</u> (rounded to the nearest whole number)

7 0

2 years ago