All categories

3 years ago

What does (2b+c)(3b+2c)=

2 answers:

6 0

6b to the second power + 4bc + 3bc + 2c to the second power

And at the end if you add it it's 6b to the second power + 7bc + 2c to the second power

I get this by first multiplying 2b by 3b and 2c getting 6b to the second power and 4bc. Next we multiply c by 3bc and 2c to the second power and get 3bc and 2c. Then you add the like terms together go puppy out add 4bc and 3bc because the are bc at the end and you get 7bc and like that the final answer is 6b to the second power + 7bc + 2c to the second power.

Svetradugi [14.3K]3 years ago

4 0

Simplify 6b2+7bc+2c2.
Hope this helps

You might be interested in

5 yrs ago, Nuri was thrice as old as Sonu. 10 yrs later, Nuri will be twice as old Sonu. How old are Nuri n Sonu?

Papessa [141]

Answer:

Answer will be 50

Step-by-step explanation:

Let us suppose, present age of Nuri be ‘x’ years and present age of Sonu be ‘y’ years.

Now, it is given that five years ago, Nuri was thrice old as Sonu. Hence,

Five years ago,

Nuri’s age = x-5 years

Sonu’s age = y-5 years

And relation between ages can be given as

Nuri’s age = 3×sonu’s age or

x-5 = 3(y-5)

x-5 = 3y-15

x-3y+10 = 0 ………..(i)

Another relation is given in the problem that ten years later, Nuri is twice as old as Sonu.

So, ten years ago,

Nuri’s Age = x+10

Sonu’s Age = y+10

And relation between ages can be written as

x+10 = 2(y+10)

x+10 = 2y+20

x-2y-10 = 0 …………..(ii)

Now we can solve the equation (i) and (ii) to get values of x and ‘y’ or present ages of Nuri and Sonu.

Value of ‘x’ from equation (i) be

x = 3y-10 ……….(iii)

Putting value of ‘x’ from equation (iii) in equation (ii) we get,

3y-10-2y-10 = 0

y = 20

Now, from equation (iii) value of ’x’ can be given as,

x= 3(20)-10

x = 50

Hence, the present ages of Nuri and Sonu are 50 years and 20 years respectively.

7 0

2 years ago

1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the

zepelin [54]

1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2

D.y=-x

2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6

C.y=-3/2x+2

3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4

4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1

B.y=-2x-1

5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)

D.y=-1/2x+5/2

5 0

2 years ago

To join the meeting vyv-vmvx-qnp

zmey [24]

Answer: yk i just a flight away if u wanna u can take a private plane

Step-by-step explanation:

Telepathia

3 0

3 years ago

The first three steps of completing the square to solve the quadratic equation x² + 4x - 6 = 0, are

slavikrds [6]

Answer: