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Alexus [3.1K]
3 years ago
7

What does (2b+c)(3b+2c)=

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
6 0
6b to the second power + 4bc + 3bc + 2c to the second power

And at the end if you add it it's 6b to the second power + 7bc + 2c to the second power

I get this by first multiplying 2b by 3b and 2c getting 6b to the second power and 4bc. Next we multiply c by 3bc and 2c to the second power and get 3bc and 2c. Then you add the like terms together go puppy out add 4bc and 3bc because the are bc at the end and you get 7bc and like that the final answer is 6b to the second power + 7bc + 2c to the second power.
Svetradugi [14.3K]3 years ago
4 0
Simplify 6b2+7bc+2c2.
Hope this helps
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8 0
3 years ago
An automotive manufacturer wants to know the proportion of new car buyers who prefer foreign cars over domestic. Step 2 of 2 : S
ziro4ka [17]

Answer:

The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

Sample of 421 new car buyers, 75 preferred foreign cars. So n = 421, \pi = \frac{75}{421} = 0.178

85% confidence level

So \alpha = 0.15, z is the value of Z that has a pvalue of 1 - \frac{0.15}{2} = 0.925, so Z = 1.44.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 - 1.44\sqrt{\frac{0.178*0.822}{421}} = 0.151

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 + 1.44\sqrt{\frac{0.178*0.822}{421}} = 0.205

The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).

8 0
3 years ago
Solve for k 5/8(3k+1)-1/4(7k+2)=1
lesya [120]

Answer:

<h2>k = 7</h2>

Step-by-step explanation:

\dfrac{5}{8}(3k+1)-\dfrac{1}{4}(7k+2)=1\qquad\text{multiply both sides by 8}\\\\8\!\!\!\!\diagup^1\cdot\dfrac{5}{8\!\!\!\!\diagup_1}(3k+1)-8\!\!\!\!\diagup^2\cdot\dfrac{1}{4\!\!\!\!\diagup_1}(7k+2)=8\cdot1\\\\5(3k+1)-2(7k+2)=8\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\(5)(3k)+(5)(1)+(-2)(7k)+(-2)(2)=8\\\\15k+5-14k-4=8\qquad\text{combine like terms}\\\\(15k-14k)+(5-4)=8\\\\k+1=8\qquad\text{subtract 1 from both sides}\\\\k=7

3 0
3 years ago
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