Question

A theater group made appearances in two cities. The hotel charges before tax in the second city were $1500 lower than in the first. The tax on the hotel bill was 8% in the first city and 10% in the second. After the trip, the total tax paid on accommodation expenses was $435 . How much was the hotel bill in the first city before tax?

Answer 1

Answer:

The hotel bill in the first city before tax would be $ 650

Step-by-step explanation:

Let x be the hotel charges ( in dollars ) before tax in the first city,

∵  Hotel charges before tax in the second city were $1500 lower than in the first.

So, the hotel charges in second city = ( x - 1500 ) dollars,

Now, percentage of tax in,

First city = 8%

Second city = 10%,

So, the total tax in both city = 8% of x + 10% of (x-1500)

$=\frac{8x}{100}+\frac{10(x-1500)}{100}$

$=0.8x + 0.10(x-1500)$

According to the question,

$0.8x + 0.10(x-1500)=435$

$0.8x + 0.10x - 150 = 435$

$0.9x = 435 + 150$

$0.9x = 585$

$\implies x = \frac{585}{0.9}=650$

Hence, the hotel bill in the first city before tax would be $ 650.

Answer 2

Answer:

the first hotel cost $4350 before tax