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4 years ago

5

How do i solve this equation?

1 answer:

FrozenT [24]4 years ago

8 0

If you took both sides to be powers of 12, you would get

12^log(5) =5 = -3k+7= 12^log(-3k+7)

can you do
5=-3k+7?

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Here is a rule for generating a sequence; 3n+10 What is the 150th term of the sequence generate by this rule?

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$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

<h3><em>Topic </em><em>-</em><em> </em><em>Arithmetic</em><em> </em><em>Progression </em><em>(</em><em> </em><em>AP </em><em>)</em></h3>

Given - <u>a </u><u>general </u><u>term </u><u>for </u><u>a </u><u>sequence.</u>

To find - <u>the </u><u>1</u><u>5</u><u>0</u><u>t</u><u>h</u><u> </u><u>term </u><u>of </u><u>the </u><u>given </u><u>sequence</u>

so let's start ~

General term , $A_{n}$ = 3n + 10

let's consider certain values of n to get some information with us which will help us solve the problem further !

let's first consider , n = 1 ! then ,

$3n + 10 = 3(1) + 10 \\ \dashrightarrow \: 13$

now , let's consider n = 2

$3n + 10 = 3(2) + 10 = 6 + 10 \\ \dashrightarrow \: 16$

then , let's consider n = 3

$3n + 10 = 3(3) + 10 = 9 + 10 \\ \dashrightarrow \: 19$

hence ,

now we've with us an AP which is as follows -

$13 \: , \: 16 \: , \: 19 \: ......$

from this Arithmetic Progression ,

we can know that

a = first term = 13

d = common difference = 16 - 13 = 19 - 16 = <u>3</u>

now ,

$A _{n} = a + (n - 1)d \\ \implies \: A _{150} = 13 + (149)(3) \\ \implies \: A _{150} = 13 + 447 \\ \pink{\implies \: A _{150} = 460}$

hope helpful :D

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