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Answer:
2/5 of 75 is 30 thats all i have for because i am haveing trouble with the same question
Step-by-step explanation:
Answer:
a. Chi-square test of independence
Step-by-step explanation:
The chi square statistics is also used to test the hypothesis about the independence of two variables each of which is classified into a number of categories or attributes.
In the given problem the Equal , more or less are the attributes.
The goodness of fit test is applicable when the cell probabilities depend upon the unknown parameters provided that the unknown parameters are replaced with their estimates and provided that one degree of freedom is deducted for each parameter estimated.
Answer:
The proportion of exam scores that are lower than Irina's score is 0.9938
Step-by-step explanation:
<u>Data</u>
- standard deviation (sd): 6 points
- value of interest (x): 95 points
z-score is computed as follows:
z = (x - mean)/sd
z = (95 - 80)/6 = 2.5
We want to find:
P(z < 2.5)
From the table attached:
P(z < 2.5) = 0.9938
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