Can someone help me with number 7. Please.

Mathematics

1 answer:

aliina [53]2 years ago

7 0

Answer:

exponent: 3; base: 4

Step-by-step explanation:

An exponent is used to signify repeated multiplication. In a typeset expression is has a superscript format. The base is the value being repeatedly multiplied.

$4^3=4\cdot4\cdot4$

The exponent is 3.

The base is 4.

_____

In plain text, an exponent is preceded by a caret (^). If the exponent consists of more than a single constant or variable, it must be enclosed in parentheses. The above expression would be written as 4^3.

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Which expression is equivalent to (5x^7+7x^8) − (4x^4−2x^8)?

I am Lyosha [343]

Simplify step-by-step
$5 {x}^{7} + 7 {x}^{8} - (4 {x}^{4} - 2 {x}^{8} )$
ANSWER
$9 {x}^{8} + 5 {x}^{7} - 4 {x}^{4}$

4 0

2 years ago

Marianne has 5/8 package of peas. She cooks 2/3 of those peas for 5 people. If each person is served an equal amount, what fract

creativ13 [48]

5/8 and 2/3 so...
8 times 3 is 24 so now put your fraction over twenty four
15/24=5/8
15/24 so fifteen out of twenty fourths of the package is what she has. She takes ten out of the fifteenths because fifteen divided by three is five then multiply by two is ten. Then divide by five and you get two.
15/24. 10-> 15/24 cause... 15 divided by 3 ( from the two thirds she cooked) is 5 then * by 2... 5*2=10

5 0

2 years ago

Please help I have a sucky teacher and don’t know what to do

Katyanochek1 [597]

Answer:

1, 4, 3, 6, 2, 7, 5

Step-by-step explanation:

The circle operator in $f\circ g$ means that the function named on the left (f) operates on the result of the function named on the right (g). So, the notation

$(f\circ g)(x)$

means

$f(g(x))$

That is, g(x) is computed and used as input to the function f. When the function definitions are as shown, the evaluation proceeds in these steps.

$(f\circ g)(-4)\\\\=f(g(-4))\quad\text{write as function of a function}\\\\=f(-2(-4)^2)\quad\text{put -4 for x in $g(x)$}\\\\=f(-2(16))\quad\text{evaluate $(-4)^2$}\\\\=f(-32)\quad\text{evaluate $g(-4)$}\\\\=2(-32-1)\quad\text{put -32 for x in $f(x)$}\\\\=2(-33)\quad\text{first step evaluating $f(-32)$}\\\\=-66\quad\text{value of $(f\circ g)(-4)$}$