Your answer is D. 2/5m
This expression means 2/5 times the initial value (m).
An equilateral triangle.
all sides are the same so the higth of the object will be the same as length of the shadow.
Answer:
11, 13, 15,
Step-by-step explanation:
have a great day :D
lol i answered ur last question also
Answer:
0.292
Step-by-step explanation:
Combinations can be used to solve the following problem.
We are choosing 5 widgets from 25 = ²⁵C₅
We want to select zero widgets from defective widgets = ⁵C₀
From the 20 non-defective widgets we want to select 5 = ²⁰C₅
So the probability is:
P = ( ⁵C₀ * ²⁰C₅) / ²⁰C₅
P = (1 * 15504) / 53130
= 15504/ 53130
=0.292 ..
Answer:
95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.
Step-by-step explanation:
Confidence interval is given by mean +/- margin of error (E)
Eggs from small nest
Sample size (n1) = 60
Mean = 37.2
Sample variance = 24.7
Eggs from large nest
Sample size (n2) = 159
Mean = 35.6
Sample variance = 39
Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11
Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93
Difference in mean = 37.2 - 35.6 = 1.6
Degree of freedom = n1+n2 - 2 = 60+159-2 = 217
Confidence level = 95%
Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132
E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79
Lower limit = mean - E = 1.6 - 0.79 = 0.81
Upper limit = mean + E = 1.6 + 0.79 = 2.39
95% confidence interval for the difference in average mass is (0.81, 2.39)