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Luba_88 [7]
3 years ago
13

Which system of equations can represent the equation log4(x+3)=log2(2+x)

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

(x + 3) = 4^{a} and (2 + x) = 2^{a}

Step-by-step explanation:

We are give that \log_{4} {(x + 3)} = \log_{2} {(2 + x)}

Now, we have to represent this equation into a system of equations.

Let, \log_{4} {(x + 3)} = \log_{2} {(2 + x)} = a

Therefore, we can write \log_{4} {(x + 3)} = a

⇒ (x + 3) = 4^{a} ........ (1)

{We know that if \log_{b} (a) = c, then converting the logarithm function to exponential function we can write a = b^{c}}

Again, we can write \log_{2} {(2 + x)} = a

⇒ (2 + x) = 2^{a} ........... (2)  

Hence, equations (1) and (2) are the required system of equations. (Answer)

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PLEASEEEEEEEEEEEEEEEEEE URGENT
jeyben [28]

Option C:

f(x) = 5x + 7 is the function of the input-output table.

Solution:

Option A: f(x) = 6x + 9

Input x = 1 in the above equation.

f(1) = 6(1) + 9

    = 6 + 9

f(1) = 15

But the output is 12 in the table.

So, it is not the function of the table.

Option B: f(x) = 7x + 5

Input x = 1 in the above equation.

f(1) = 7(1) + 5

f(1) = 12

Input x = 5 in the above equation.

f(5) = 7(5) + 5

f(5) = 40

But the output is 32 in the table.

So, it is not the function of the table.

Option C: f(x) = 5x + 7

Input x = 1 in the above equation.

f(1) = 5(1) + 7

f(1) = 12

Input x = 5 in the above equation.

f(5) = 5(5) + 7

f(5) = 32

Input x = 10 in the above equation.

f(10) = 5(10) + 7

f(10) = 57

Input x = 5 in the above equation.

f(15) = 5(15) + 7

f(15) = 82

All outputs are correct for the given input.

Hence it is the function of the table.

Option D: f(x) = 12x + 1

Input x = 1 in the above equation.

f(1) = 12(1) + 1

f(1) = 12

Input x = 5 in the above equation.

f(5) = 12(5) + 1

f(5) = 61

But the output is 32 in the table.

So, it is not the function of the table.

Hence Option C is the correct answer.

f(x) = 5x + 7 is the function of the input-output table.

4 0
3 years ago
The radius of a sphere is measured to be 3.0 inches. If the measurement is correct within 0.01 inches, use differentials to esti
Zarrin [17]

Answer:

ΔV = 0.36π   in³

Step-by-step explanation:

Given that:

The radius of a sphere = 3.0

If the measurement is correct within 0.01 inches

i.e the change in the radius Δr = 0.01

The objective is to use differentials to estimate the error in the volume of sphere.

We all know that the volume of a sphere

V =  \dfrac{4}{3} \pi r^3

The differential of V with respect to r is:

\dfrac{dV}{dr }= 4 \pi r^2

dV = 4 πr² dr

which can be re-written as:

ΔV = 4 πr² Δr

ΔV = 4 × π × (3)² × 0.01

ΔV = 0.36π   in³

5 0
3 years ago
Mary bought a handbag for 15.00naira. if she sold it for 18.00,what was her percentage gain?​
melomori [17]

Answer:

total profit gained = 20%

Step-by-step explanation:

profit = SP - CP = 18 - 15 = 3 naira

total profit percentage =

  • ( profit / CP ) × 100
  • 3 / 15 × 100
  • 20%

hence her total percentage gain was 20%

8 0
3 years ago
Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that
amm1812

Answer:

The value is  P(| \^ p -  p| < 0.05 ) = 0.9822

Step-by-step explanation:

From the question we are told that

    The population proportion is  p =  0.52

     The sample size is  n  =  563      

Generally the population mean of the sampling distribution is mathematically  represented as

           \mu_{x} =  p =  0.52

Generally the standard deviation of the sampling distribution is mathematically  evaluated as

       \sigma  =  \sqrt{\frac{ p(1- p)}{n} }

=>      \sigma  =  \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }

=>      \sigma  =   0.02106

Generally the  probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

            P(| \^ p -  p| < 0.05 ) =  P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 ))

  Here  \^ p is the sample proportion  of persons with a college degree.

So

 P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma }  < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )

Here  

    \frac{[\^p - p] - p}{\sigma }  = Z (The\ standardized \  value \  of\  (\^ p - p))

=> P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = P[\frac{-0.47 - 0.52}{0.02106 }  <  Z  < \frac{-0.47 + 0.52}{0.02106 }]

=> P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = P[ -2.37 <  Z  < 2.37 ]

=>  P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = P(Z <  2.37 ) - P(Z < -2.37 )

From the z-table  the probability of  (Z <  2.37 ) and  (Z < -2.37 ) is

  P(Z <  2.37 ) = 0.9911

and

  P(Z <  - 2.37 ) = 0.0089

So

=>P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) =0.9911-0.0089

=>P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = 0.9822

=> P(| \^ p -  p| < 0.05 ) = 0.9822

3 0
4 years ago
What is 4.06 increased by 17?<br><br>please help me ​
Dafna1 [17]

Answer:

21.06

Step-by-step explanation:

4.06 increased by 17

4.06 + 17

21.06

4 0
3 years ago
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