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Sonja [21]
4 years ago
10

A towns population is 43,425. About 125 people move out of the town each month. Each month, 200 people on average move into town

. A nearby town has a population of 45,000. It has no one moving in and an average of 150 people moving away every month. DO BOTH OF THESE THINGS!!! 1) In about how many months will the population of the towns be equal? 2) WRITE an equation that represents this situation and solve!!!!!
Mathematics
1 answer:
jolli1 [7]4 years ago
5 0

Answer 1) x = 7 so in 7 months

2) 43,425 + 75x = 45,000 - 150x

Step-by-step explanation:

basically town A is gaining 75 people monthly and town B is decreasing 150 monthly so 43,425 + 75x = 45,000 - 150x and then you find out in 7 months both town will have equal population hope i helped

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s2008m [1.1K]

Answer:

x = -3

y = 0

Step-by-step explanation:

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<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u>

<u>From</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u><u> </u><u> </u>

<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u>

<u>-x</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>-</u><u> </u><u>2</u><u>y</u><u> </u>

<u>x</u><u> </u><u>=</u><u> </u><u>2</u><u>y</u><u> </u><u>-</u><u> </u><u>3</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>iii</u><u> </u><u>)</u>

<u>From</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u><u> </u>

<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u>

<u>2</u><u>x</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>+</u><u> </u><u>3</u><u>y</u><u> </u>

<u>x =  \frac{ - 6 + 3y}{2}</u>

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3 years ago
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6 0
2 years ago
A certain genetic condition affects 8% of the population in a city of 10,000. Suppose there is a test for the condition that has
enot [183]

Solution:

Population in the city= 10,000

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8 % of 10,000

=\frac{8}{100}\times 10,000=800

As, it is also given that, there is an error rate of 1% for condition (i.e., 1% false negatives and 1% false positives).

So, 1% false negatives means out of 800 tested who are found affected , means there are chances that 1% who was found affected are not affected at all.

So, 1% of 800 =\frac{1}{100}\times 800=8

Also,  1% false positives means out of 10,000 tested,[10,000-800= 9200] who are found not affected , means there are chances that 1% who was found not affected can be affected also.

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2. Test positive =92

3. Test negative =8

4. Total =800 +92 +8=900

5. Probability (as a percentage) that a person has the condition if he or she tests positive= As 8% are found positive among 10,000 means 9200 are not found affected.But there are chances that out of 9200 , 1% may be affected

=\frac{\text{1 percent of 9200}}{9200}\\\\ \frac{\frac{1}{100}\times 9200}{9200}=\frac{92}{9200}\\\\ =0.01

that is Probability equal to 0.01 or 1%.

7 0
3 years ago
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