This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
The greatest difference you can get is 42
The range of the integer is given as:
Smallest = -16
Largest = 26
So, the range is calculated as:
Range = Largest - Smallest
Substitute known values
Range = 26 - (-16)
Evaluate the difference
Range = 42
Hence, the greatest difference you can get is 42
Read more about range at:
https://brainly.in/question/6887467
Answer:
a shs s s s ss bsbsbsbs s s s s s s s s s s s s s
Answer:
it is an interior alternate angle and x= 27
Step-by-step explanation:
This question is incomplete, the complete question is;
For integers a, b and k, we know that a > 12, b < 20 and a < b. If b=7k, what is the value of k ?
Answer: the value of k = 2
Step-by-step explanation:
Given that;
a > 12
b < 20
a < b
If b = 7k
Now if k = 1 {b = 7k = 7}
b would be equal to 7 but b has to be greater than 20
IT CANT BE
if k = 2 { b = 7k = 14}
b would be equal to 14, a is greater than 12, b has to be less than b; 14 < 20,
a has to be less than than b ( 12 < 14 )
IT IS
if k = 3 {b = 7k = 21}
b would be equal to 21, so b is greater than 20 and a is less than 21
IT CANT BE
Therefore the value of k = 2
