If f(x) = 3x^2 – 2x + 4 and g(x) = 5x^2 + 6x – 8, find (f - g)(x).

Mathematics

2 answers:

Alika [10]3 years ago

7 0

(f-g)(x)=f(x)-g(x)

=((3x^2)-2x+4)-((5x^2)+6x-8)

=(-2x^2)-8x+12

The answer is -2x^2 -8x+12. I hope this helps.

meriva3 years ago

5 0

Answer:

$-2x^2-8x+12$

Step-by-step explanation:

$f-g=(3x^2-2x+4)-(5x^2+6x-8)=3x^2-2x+4-5x^2-6x+8=\\ =-2x^2-8x+12$

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The graph is indicated in the attached figure.

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$d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\$