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andrey2020 [161]
3 years ago
11

Please help! Solve for y. 2x+5y=4 Solve for t. A=p+prt

Mathematics
1 answer:
Elan Coil [88]3 years ago
4 0
1. y=(4-2x)/5
2. t=(A-p)/pr
OR
t=A/pr - 1/r
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How do you graph this f(x)= -3/2|x|+5 if x≤4​
LenaWriter [7]

Answer:

  see below

Step-by-step explanation:

I enter the equation into a graphing calculator and let it do the graphing.

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If you're graphing this by hand, you start by looking for the parent function. Here, it is |x|. That has a vertex of (0, 0) and a slope of +1 to the right of the vertex and a slope of -1 to the left of the vertex.

Here, the function is multiplied by -3/2, so will open downward and have slopes of magnitude 3/2 (not 1). The graph has been translated 5 units upward, so the vertex is (0, 5).

I'd start by plotting the vertex point at (0, 5), then identifying points with slope ±3/2 either side of it. To the left, it is left 2 and down 3 to (-2, 2). The points on the right of the vertex are symmetrically located about the y-axis, so one of them will be (2, 2).

Of course, you don't plot any function values for x > 4.

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3 years ago
PLEASE HELP Tony has $50.60 in his bank account and plans to add to it each week when he gets paid.
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3 years ago
The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st
Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

v=\frac{d}{t}.

Applying this to our problem we have that

v=\frac{200m}{6.509s}= 30.726m/s.

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that v=\frac{d}{t}. This formula implies that

  1. t=\frac{d}{v}.

First, observer that 19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s.

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.

Then, applying 1) we have that

t=\frac{200m}{36.003m/s}=5.5549s.

So, Sam Whittingham’s time through the 200 m was 5.5549s.

5 0
3 years ago
At midnight, the outside temperature was -12.3 degrees. By 6:00 AM the outside tempature had dropped 6.8 degrees.
choli [55]
It was -19.1 degrees
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3 years ago
Find the zeros of the quadratic function f(x) = 2x2 - 8x + 6 from the graph
Assoli18 [71]

Answer: X=3,1

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Step-by-step explanation: Have a nice day

5 0
3 years ago
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