Answer:
nkvndkfhbkbhjbdhbhbfdhbkxcx
Step-by-step explanation:
vchdksbkfgbkbkhbdhbbhbshbfhklkgfsfg
Answer:
36
Step-by-step explanation:
Since f(x) varies directly with x, f(x) can be expressed alternatively as \[f(x) = k * x\] where k is a constant value.
Given that f(x) is 72 when the value of x is 6.
This implies, \[72 = k * 6\]
Simplifying and rearranging the equation to find the value of k:
k = \frac{72}{6}
Hence k = 12
Or, \[f(x) = 12 * x\]
When x = 3, \[f(x) = 12 *3 \]
Or in other words, the value of f(x) when x=3 is 36
49^2m-m : Not equivalent
7^2m-2m : Not equivalent
7^2m-m : Not equivalent
This is actually a trick question. All of the following are actually false statements. Want to know why? Let me show you.
For exponents, if you are dividing a number to some power (i.e 5^3) by the SAME number to a different power (i.e 5^2), then the expression is 5^3-2 or 5^1 = 5. This is true for any number a such that a^b ÷ a^c = a^b-c.
Since 7 and 49 are not the same number, this rule does not apply and thus cannot be simplified any further.
Let me prove why. 5^3 = 125, and 5^2 = 25, and 125 ÷ 25 = 5. This is also the same as 5^3-2 = 5^1 = 5. We just proved this as so.
But, what about 7 and 49, or 2 different numbers. Well it doesn't apply. 7^3 = 343, and 49^2 = 2401, and 343 ÷ 2401 ≈ 0.14. Thus, this is NOT equal to 7^3-2 which is 7. We just proved that a^y ÷ b^z ≠ a^y-z. Congratulations!
Hope this helped!
