Find the dimensions of a rectangular piece of property that has a perimeter of 610 feet if the length is twenty feet more than t

Question

cricket20 [7]

3 years ago

10

Find the dimensions of a rectangular piece of property that has a perimeter of 610 feet if the length is twenty feet more than t

wo times the width

Mathematics

1 answer:

sp2606 [1] · Answer 1 · 2022-01-15T21:25:48+03:00

sp2606 [1]3 years ago

4 0

2L + 2W = 610L = 2W + 20 Substitute the second equation into the first: 2(2W + 20) + 2W = 610 Solve for W. 4W + 40 + 2W = 6106W = 570W = 95 Use the second equation to solve for L