Answer:
P(X > 126) = 0.2119
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

P(X > 126) is the 1 subtracted by the pvalue of Z when X = 126. So


[tez]Z = 0.8[/tex]
[tez]Z = 0.8[/tex] has a pvalue of 0.7881.
P(X > 126) = 1 - 0.7881 = 0.2119
I cant answer that, I dont know why????! I usually do!!
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➷ Just work with what is inside the parenthesis
Also, move around the terms to help it make more sense:
(cosA cosB - cosA cosB + sinA sinB + sinA sinB)
As you can see, the 'cosA cosB' would cancel out through subtraction.
Now we have this:
(sinA sinB + sinA sinB)
This is just two sets of sinA sinB so it can be written as:
(2 * sinA sinB)
Simply place the values outside the parenthesis back there to get the answer
SinA sinB = 1/2 * (2 * sinA sinB)
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➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
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Answer:
here u go
Step-by-step explanation:
88%
Answer:
C
Step-by-step explanation:
Subtract column by column from the left, that is
6x² - 3x² = 3x²
- 5x - (+ 8x) = - 5x - 8x = - 13x
3 - (- 4) = 3 + 4 = 7
result of subtraction = 3x² - 13x + 7 → C