Answer:
I THINK IT WILL BE HELPFUL
Answer:
Step-by-step explanation:
Remark
You need the work done (I think), and the power developed from the givens. This question is just a straight forward application of the formulas for work and power.
Givens
F = 100 N
d = 5 meters
t = 15 seconds
Formulas
W = F * d
Power = F * d / t
Solution
<u><em>Work</em></u>
W = 100 N * 5 meters
W = 500 Newton Meters or 500 J
Work = 500 Joules
<u><em>Power</em></u>
P = F * d / t
Power = 100 * 5 / 15
Power = 33.3 Watts.
Answer:
x = 2, y = 6
(2, 6)
Step-by-step explanation:
The system of equations is solved when we find the "x" and "y" pair that is true for both equations.
We can use elimination, which is when we eliminate one of the variables. This can be done when both equations have a variable that has the same number.
Make both equations have "12y". Multiply each term by the same number.
-7x + 4y =10 }x3 => -21x + 12y = 30
-5x + 3y = 8 }x4 => -20x + 12y = 32
Subtract the equations from each other to get rid of 12y.
. -20x + 12y = 32
<u>- -21x + 12y = 30</u>
. 1x + 0y = 2 0y is nothing and 1x is x.
. x = 2 We have solved for x.
Now solve for y.
Use one of the equations:
-5x + 3y = 8 Substitute x for 2
-5(2) + 3y = 8 Simplify
-10 + 3y = 8 Start isolating x. Add 10 to both sides
3y = 18 Divide both sides by 3
y = 6 Solved for y.
The system of equations intersect at (2, 6).
It is the 1st equation at the top.
Reason: First check the equations to check that the initial amount is 497 kg. You can do this by setting x = 0 into all of the equations. The 3rd and 4th equations evaluate to 2 when x = 0 and so you can eliminate the bottom 2 equations immediately. Equation # 2 does not work since the half-life value of 1.040 kg is way to small (significantly smaller than half of 497 kg).
You can check that equation # 1 is the right one, by setting x = 0 and getting
y = 497*(1/2)^[(1/38) * 0] = 497
so the initial amount is 497
Also check that there is 1/2 the amount at time 38 (since the half-life is 38 days)
y = 497 * (1/2)^[(1/38) * 38] = 248.5
248.5 kg is half of 497 and so this checks out for equation # 1.
Since we know equation # 1 is good, now we evaluate at x = 4 to get
y = 497 * (1/2)^[(1/38) * 4] = 462.029
so our answer to the thousandth places is 462.029 kg.
