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3 years ago

Please can someone help me with my maths? I’m so confused

Mathematics

1 answer:

Blababa [14]3 years ago

5 0

The y intercept is 0.5 because thats where the line starts.
the slope/gradient of the line is 1.5.
this would be written in the form: y=1.5x+0.5

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X^2 - 16 = 0 by extracting the square root

scoray [572]

Answer:

{-4, 4}

Step-by-step explanation:

x² - 16 = 0
x² = 16
x = √16
x = ± 4

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2 years ago

FIRST PERSON TO ANSWER GETS BRAINLIEST OR FIVE STARS Define the domain and range of the function.

uysha [10]

Answer:

Domain: (-∞, ∞)

Range: (-∞, ∞)

Step-by-step explanation:

The domain are the x-values included in the function (the horizontal axis).

The range are the y-values included in the function (the vertical axis).

The two arrows on the ends of the line (pointing upwards and downwards respectively) indicate that the function goes in those direction for infinity. Therefore, if there are an infinite amount of y-values, the range is (-∞, ∞).

While the slope is quite steep, there is still a slope and slowly "expands" the line on the horizontal axis. Because there is no limit to the y-values, the domain will also expand infinitely. Therefore, the domain is also (-∞, ∞).

7 0

1 year ago

Read 2 more answers

The ratio of teachers to students at a school is 3:74 there are 2500 students at the school about hiw many teachers are at the s

zhannawk [14.2K]

Answer:

The answer is 101. There are 101 teachers.

8 0

3 years ago

B. Determine the values of a and b so that f is continuous.<br><br> Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$

So, the value of $a \ and \ b= \frac{1}{2}$

4 0

2 years ago

Factorise completely 4ab+6ac-6bd-9cd

Naily [24]

Answer:

(2b+3c) × (2a-3d)

Step-by-step explanation:

plz mark as brainliest

6 0

2 years ago