Answer:
Distance between school and home = 105 miles.
Step-by-step explanation:
Let distance = D miles
Time to take walking/jogging, t1 = D/6 hours
Time by car, t2 = D/35 hours
Average time, t
= (t1+t2)/2
= D(1/6+1/35)
= (D/210)(35+6)
=41D/210 hours
Given t = t1-3 hours
41D/210 - D/6 = 3
Solve for D
41D/210 - 35D/210 = 3
(41-35)D/210 = 3
6D/210 = 3
D = 3*210/6 = 105 miles.
(Appreciate very much Diana's efforts to walk/job 105 miles to school, and we understand how lucky we are in most of Europe and North America)
The maximum possible length it could have been is 38.9
Greetings!
"<span>Heather measured a swimming pool and made a scale drawing. In real life, the pool is 45 meters long. It is 65 millimeters long in the drawing. What scale did Heather use for the drawing?"...
65mm=</span>45m<span>
Reduce to Simpliest Form.
</span>65/5=<span>45/5
13mm=9m
As a Representative Fraction (scale), it would look like: (in regards to mm)
13:9000
Hope this helps.
-Benjamin</span>
ZW = WM and YP = PT
This means line PW is the middle of the shape.
PW = 29
YZ = 23
29-23 = 6
There is a difference of 6 btween the top line and the middle line, so there needs to be a difference of 6 from ther middle line to the bottom line.
The bottom line needs to equal: 29 +6 = 35
11x +2 = 35
Subtract 2 from each side:
11x = 33
Divide both sides by 11:
x = 33/11
x = 3
The answer is B.
