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Wittaler [7]
3 years ago
10

Please can someone help me with my maths? I’m so confused

Mathematics
1 answer:
Blababa [14]3 years ago
5 0
The y intercept is 0.5 because thats where the line starts.
the slope/gradient of the line is 1.5.
this would be written in the form: y=1.5x+0.5
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Given that lines m and n are parallel and m<60, find the measures of the remaining angles m<3=?
grigory [225]

When you have two parallel lines being cut by a transversal, you can use the next statements for the angles:

The measurement of the angles in green is the same (are congruents)

The measurement of the angles in blue is the same (are congruents)

An angle in green is a complementary angle with an angle in blue. (The addition of the two angles has to be 180º)

You know that:

m\angle2=60º

As the angle 3 is congruent with angle 2:

m\angle3=60º

6 0
11 months ago
Find the quadratic function that has roots of -9 and 3 and a vertex of (-3,-36)
natita [175]
Y=(x+9)(x-3)+c
∵(-3,-36)lies on it.
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3 years ago
given a soda can with a volume of 15 and a diameter of 2, what is the volume of a cone that fits perfectly inside the soda can (
Paul [167]

Answer:

sorry but can you answer my question first

Step-by-step explanation:

brainly.com/question/17587885

7 0
3 years ago
Please help me please
kobusy [5.1K]
Terrell ran 1,000 meters more than Victor. That's the answer because if you know 1 kilometer = 1,000 meters than do 3 kilometers times 1 kilometer = 3,000 meters. Than do 4,000 meters -3,000 meters  to get 1,000 meters. so the answer is Terrell ran 1,000 meters more than Victor. 
7 0
3 years ago
Un móvil azul de 573 g se encuentra en movimiento sobre un carril metálico. Si sobre el móvil, el resorte ejerce una fuerza haci
ad-work [718]

Answer:

The total mechanical energy is 0.712 J.

Step-by-step explanation:

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The total mechanical energy is given by the sum of the kinetic energy and the potential energy.

Kinetic energy = 0.47 J

Potential energy = 0.242 J

The total mechanical energy is

T = 0.47 + 0.242 = 0.712 J

4 0
2 years ago
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