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grin007 [14]
3 years ago
6

Show the stack with all activation record instances, including static and dynamic chains, when execution reaches position 1 in t

he following skeletal program. Assume bigsub is at level 1.
function bigsub() {

function a() {

function b() {

... <----------------------------1

} // end of b

function c() {

...

b();

...

} // end of c

...

c();

} // end of a

...

a();

...

}// end of bigsum
Computers and Technology
1 answer:
astraxan [27]3 years ago
6 0

Answer:

Activation Records

The storage (for formals, local variables, function results etc.) needed for execution of a

subprogram is organized as an activation record.

An Activation Record for “Simple” Subprograms

.

Activation Record for a Language with Stack-Dynamic Local Variables

Dynamic link: points to the top of an activation record of the caller

Explanation:

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Answer:

360°

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Which Internet resource can you use to publicly describe an adventure trip you recently made?
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Assume that nextWord is a String variable that has been given a String value consisting entirely of letters. Write some Java cod
wel

Answer:

The code example is given below with explanation in c++ language.

Explanation:

Comments will explain what's going on in the code. Below code is already compiled and tested.

#include <time.h>

#include <iostream>

#include <sstream>

using namespace std;

int main(void)

{

//defining start and end time variable

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   time_t endwait;

   time_t start = time(NULL);

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cout<<"Input your number :";

long userNum;

cin>> userNum;

// initializing end time by adding seconds with start time

   endwait = start + seconds;

   // defining outputString which will concatenate all the  

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string outputString="";

// bool isCompleted will use to check whether our  

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bool isCompleted=true;

// iterate loop until it comes to 1. as in loop

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   while (userNum>1)

   {  

  // checking start and end time comparison to  

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    if(start >= endwait){

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     isCompleted=false;

     break;

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   // re initializing the start time with current time.

       start = time(NULL);

   }

   

  // check if while loop breaks successfully then print the

   // series of numbers here.

   if(isCompleted) {

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}

   return 0;

}

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A software is made from​
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Answer:

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Please specify the programming language.


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