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grin007 [14]
3 years ago
6

Show the stack with all activation record instances, including static and dynamic chains, when execution reaches position 1 in t

he following skeletal program. Assume bigsub is at level 1.
function bigsub() {

function a() {

function b() {

... <----------------------------1

} // end of b

function c() {

...

b();

...

} // end of c

...

c();

} // end of a

...

a();

...

}// end of bigsum
Computers and Technology
1 answer:
astraxan [27]3 years ago
6 0

Answer:

Activation Records

The storage (for formals, local variables, function results etc.) needed for execution of a

subprogram is organized as an activation record.

An Activation Record for “Simple” Subprograms

.

Activation Record for a Language with Stack-Dynamic Local Variables

Dynamic link: points to the top of an activation record of the caller

Explanation:

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Consumer report would help determine the best technology to buy.
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3 years ago
OSHA requires training for employees on the hazards to which they will be exposed.
Sedaia [141]

A, OSHA does require training for employees on the hazards to which they will be exposed.


3 0
4 years ago
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) Consider a router that interconnects four subnets: Subnet 1, Subnet 2, Subnet 3 and Subnet 4. Suppose all of the interfaces in
erik [133]

Answer:

Check the explanation

Explanation:

223.1.17/24 indicates that out of 32-bits of IP address 24 bits have been assigned as subnet part and 8 bits for host id.

The binary representation of 223.1.17 is 11011111 00000001 00010001 00000000

Given that, subnet 1 has 63 interfaces. To represent 63 interfaces, we need 6 bits (64 = 26)

So its addresses can be from 223.1.17.0/26 to 223.1.17.62/26

Subnet 2 has 95 interfaces. 95 interfaces can be accommodated using 7 bits up to 127 host addresses can represented using 7 bits (127 = 27)

and hence, the addresses may be from 223.1.17.63/25 to 223.1.17.157/25

Subnet 3 has 16 interfaces. 4 bits are needed for 16 interfaces (16 = 24)

So the network addresses may range from 223.1.17.158/28 to 223.1.17.173/28

4 0
3 years ago
Two cars A and B leave an intersection at the same time. Car A travels west at an average speed of x miles per hour and car B tr
drek231 [11]

Answer:

Here is the C++ program:

#include <iostream>  // to use input output functions

#include <cmath>  // to use math functions like sqrt()

#include <iomanip>  //to use setprecision method

using namespace std;   //to access objects like cin cout

int main ()  {  //start of main function

  double speedA;  //double type variable to store average speed of car A

  double speedB;  //double type variable to store average speed of car B

  int hour;  //int type variable to hold hour part of elapsed time

  int minutes;  //int type variable to hold minutes part of elapsed time

  double shortDistance;  // double type variable to store the result of shortest distance between car A and B

  double distanceA;  //stores the distance of carA

  double distanceB;  //stores the distance of carB

  double mins,hours;   //used to convert the elapsed time

cout << "Enter average speed of car A: " << endl;  //prompt user to enter the average speed of car A

cin >> speedA;   //reads the input value of average speed of car A from user

cout << "Enter average speed of car B: " << endl ;  //prompt user to enter the average speed of car B

cin >> speedB;   //reads the input value of average speed of car A from user

cout << "Enter elapsed time (in hours and minutes, separated by a space): " << endl;  //prompts user to enter elapsed time

cin>> hour >> minutes;    //reads elapsed time in hours and minutes

  mins = hour * 60;  //computes the minutes using value of hour

  hours = (minutes+mins)/60;     //computes hours using minutes and mins

distanceA = speedA * (hours);  // computes distance of car A

distanceB = speedB * (hours);   //computes distance of car B

   shortDistance =sqrt((distanceA * distanceA) + (distanceB * distanceB));   //computes shortest distance using formula √[(distanceA)² + (distanceB)²)]

cout << "The (shortest) distance between the cars is: "<<fixed<<setprecision(2)<<shortDistance;

//display the resultant value of shortDistance up to 2 decimal places

Explanation:

I will explain the program with an examples:

Let us suppose that the average speeds of cars are:

speedA = 70

speedB = 55

Elapsed time in hours and minutes:

hour = 2

minutes = 30

After taking these input values the program control moves to the statement:

mins = hour * 60;  

This becomes

mins = 2 * 60

mins = 120

Next

hours = (minutes+mins)/60;

hours = (30 + 120) / 60

         = 150/60

hours = 2.5

Now the next two statements compute distance of the cars:

distanceA = speedA * (hours);  

this becomes

distanceA = 70 * (2.5)

distanceA = 175

distanceB = speedB * (hours);

distanceB = 55 * (2.5)

distanceB = 137.5

Next the shortest distance between car A and car B is computed:

shortDistance = sqrt((distanceA * distanceA) + (distanceB * distanceB));

shortDistance = sqrt((175 * 175) + (137.5 * 137.5))

                        = sqrt(30625 + 18906.25)

                        = sqrt(49531.25)

                        =  222.556173

shortDistance =  222.56

 

Hence the output is:

The (shortest) distance between the cars is: 222.56        

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3 years ago
Lori wants to set up a SOHO network in her apartment. The apartment comes with a Gigabit Ethernet network already installed. Lor
Yanka [14]

Connection to the gigabit ethernet network must be done with Cat6 Cable. Using the wireless ethernet router as the network device and connecting the cable to the printer must be done with Cat5e Cable.

We can arrive at this answer because:

  • The Cat6 Cable will be responsible for establishing a bridge between the gigabyte Ethernet and the network device, allowing data delivery to be made between the two systems.
  • This connection must be made with a wireless device, to keep it more stabilized and it needs, mainly, for the notebook to receive the internet signal. This will be done using the wireless ethernet router.
  • The printer needs a softer, less rigid connection, so a Cat5e cable will be a convenient option.

In this case, we can see that using these devices will allow Lori to have a more stable and efficient connection to meet her needs.

More information on network connection at the link:

brainly.com/question/8118353

5 0
2 years ago
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