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IrinaK [193]
3 years ago
11

What is the equation of the line​

Mathematics
1 answer:
Travka [436]3 years ago
6 0

Answer:

\boxed {y = \frac{4}{5}x + 4}

Step-by-step explanation:

Determine the graph by using the <em><u>rise over run</u></em>. Since the line shows that it is increasing (up), then the slope is positive:

Rise = 4

Run = 6

m = \frac{4}{5}

After you have found the slope, find the <u>y-intercept</u>, which when the line crosses the <u>y-axis</u>:

Y-intercept = 4

-Since you now have the slope and y-intercept, use them to form a <u>Slope-Intercept form</u>:

y = mx + b

Apply them to the equation:

\boxed {y = \frac{4}{5}x + 4}

<u />

<em><u /></em>

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Select the correct answer. What is the 13th term of this arithmetic sequence? 132, 135, 138, 141, … A. 168 B. 172 C. 176 D. 179
puteri [66]

Answer:

168

Step-by-step explanation:

132, 135, 138, 141, 144, 147, 150, 153, 156, 159, 162, 165, 168

5 0
3 years ago
HELP ME ITS TIMED AND I WILL GIVE BRAINLIEST!!!!!
Olegator [25]

To find the gradient of a line we first hv to find the formula

so Gradient=√X1-x2and √y1-y2

((-2,1) and (0,-5)) line 1

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first we will work for line 1

X1 is -2

X2 is -0

Y1 is 1

Y2 is -1

so y=x-1

so we substitute the values

1--1=-2--0

so,

1+1=-2+0

2=-2

-0

So the equation 1 line 1 is not true

we will now go to equation 2 line 2

the equation is 3x+y=-5

we substitute the values

3(-2--0)+1--1=-5

3(-2)+-2=-5

-6+-2=-5

-8= -5

group like terms

Ur answer should look like this -3

So the answer is 3x+y=-5

7 0
3 years ago
the perimeter of an equilateral triangle equals 3 times the length of one side. write a function using 2 variables for this situ
ValentinkaMS [17]
I hope this helps you

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3 years ago
A certain forest covers an area of 4300 km2 . suppose that each year this area decreases by 3.25% . what will the area be after
Gemiola [76]
A =P(1-3.25%)⁸

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A 273,000-gallon shipment of fuel is 2.3 percent
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Answer:

Amount of fuel antifreeze = 6,279 gallon

Step-by-step explanation:

Given:

Amount of fuel =  273,000-gallon

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