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vesna_86 [32]
3 years ago
5

Lincy is standing 20 feet from the circular wall of an above ground swimming pool and 49 feet from a point of tangency. Find the

radius of the pool.
Mathematics
1 answer:
BaLLatris [955]3 years ago
7 0

Answer:

the radius of the pool is 50.025 feet

Step-by-step explanation:

From the information given:

We can have a schematic view of a diagrammatic illustration in our mind where the distance of the pool to Lincy is (20 + r ) and the distance to the tangent is 49.

So; by using pythagoras theorem, since the radius meets the tangent at a right angle; we have:

r^2 + 49^2 = ( r + 20 )^2

r^2 +2401 = r^2 + 40r + 400

2401 =   40r + 400

2401-  400  =   40r

2001 = 40 r

r = 2001/40

r = 50.025 feet

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rewona [7]

check the picture below.

now, we're assuming the trapezoid is an isosceles trapezoid, namely AD = BC, and therefore the triangles are twins.

incidentally, b is the height of the trapezoid and likewise is also the altitude or height of the concrete triangle.

so we can simply get the area o the trapezoid, notice the bottom base is a+185+a, and then get the area of the concrete triangle and subtract the triangle from the trapezoid, what's leftover is just the vegetation area.

\bf \begin{cases} a=283\cdot cos(80^o)\\ a\approx 49.14\\ --------\\ b=283\cdot sin(80^o)\\ b\approx 278.70 \end{cases}\\\\ -------------------------------\\\\ \textit{area of a trapezoid}\\\\ A=\cfrac{h(x+y)}{2}~~ \begin{cases} x,y=\stackrel{bases}{parallel~sides}\\ h=height\\ ----------\\ x=185\\ y\approx \stackrel{a+185+a}{283.28}\\ h\approx\stackrel{b}{278.70} \end{cases} \\\\\\ A=\cfrac{278.70(185+283.28)}{2}\implies A\approx 65254.818

so that's the area of the trapezoid, now let's get the area of the triangle.

\bf \stackrel{triangle}{\cfrac{1}{2}(185)(b)}\implies \cfrac{1}{2}(185)(278.70)\qquad \approx 25779.80\\\\ -------------------------------\\\\ \stackrel{\textit{area for vegetation}}{\stackrel{\textit{area of trapezoid}}{65254.818}~~-~~\stackrel{\textit{area of triangle}}{25779.80}}\implies 39475.018

since we know 36 yd² cost 12 bucks, then how much will it be for 39475.018 yd²?

\bf \begin{array}{ccll} yd^2&\$\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 36&12\\ 39475.018&x \end{array}\implies \cfrac{36}{39475.018}=\cfrac{12}{x}\implies x=\cfrac{39475.018\cdot 12}{36} \\\\\\ x\approx 13158.339\overline{3}

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Which description best compares the graphs given by the equations:
nexus9112 [7]

x - 5y = -5, -5x - 25y = 25

First, you'll need to get the x variable by itself.

x - 5y = -5<u>
</u><u>    +5    +5</u><u>
</u>       x = 0
So x is plotted on the 0.

For the second part of the first equation, you'll be looking for what the y variable represents.

x - 5y = -5
<u>-x           -x</u><u>
</u>     <u>-5y</u> = <u>-5</u><u>
</u><u>       5      5</u><u>
</u>        y = 1
So y is plotted on the 1 on the vertical line above the 0.

For the first part of the second equation, you'll do the same thing as in the first equation.

-5x - 25y = 25
<u>        +25   +25</u><u>
</u>          <u>-5x</u> = <u>50</u><u>
</u>            5      5
            x = 10
So the x for this equation is plotted on 10 on the horizontal line.

For the second part of the second equation, you will do the same thing as in the first equation.

-5x - 25y = 25
<u>+5               +5</u><u>
</u>       <u>-25y</u> = <u>30</u><u>
</u>        25      25
           y = 1.2
So the y for the second half of the second question is plotted on 1.2 on the vertical line.

<h2>Answer: B) Perpendicular</h2>

Perpendicular means the lines may or may not be of equal length and they will not be perfectly in line with each other.

Parallel means the lines may or may not be of equal length but will be perfectly in line with each other.

Intersecting means the lines may or may not be of equal length but will touch each other.

6 0
2 years ago
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