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3 years ago

Help Please! Lots of points

Mathematics

2 answers:

8090 [49]3 years ago

7 0

Answer:

35%

Step-by-step explanation:

Assume that the radius of the circle is 1.

The diagonal of the square is 2. By the Pythagorean Theorem, the side of the square of a right triangle will be 2/sqrt(2).

Finally, the ratio of the square to the circle, in area, will be

(2/sqrt(2))^2 : pi*(1)^2 = 2 : pi

We can conclude that the white area is about 35%.

]

scoundrel [369]3 years ago

3 0

Assume that the radius of the circle is 1.

The diagonal of the square is 2. By the Pythagorean Theorem, the side of the square of a right triangle will be 2/sqrt(2).

Finally, the ratio of the square to the circle, in area, will be

(2/sqrt(2))^2 : pi*(1)^2 = 2 : pi

We can conclude that the white area is about 35%.

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DochEvi [55]

Answer:

2s+5p=40

Step-by-step explanation:

s=sodas

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3 years ago

This is due like right now, please help me!!!!

Varvara68 [4.7K]

$\bold{\huge{\orange{\underline{ Solution }}}}$

$\bold{\underline{ Given \: Rules}}$

The sum of the number in each of the four rows is the same
The sum of the numbers in each of the three columns is the same
The sum of any row does not equal the sum of any column

$\bold{\underline{ Let's \: Begin}}$

According to the Second rule :-

$\sf{ 75+b+83=76+80+d=a+81+85+78+c+e }$

$\sf{ 158 + b = 156 + d = 166 + a = 78 + c + e ...(1)}$

According to the first rule :- 

$\sf{ 75+76+a+78 = b+80+81+c = 83+86+d+e}$

$\sf{ 229 + a = 161 + b + c = 168 + d + e ...(2)}$

From ( 1 ) we got :-

$\sf{ 158 + b = 166 + a, 156 + d = 166 + a }$

$\sf{ b = 166 - 158 + a, d = 166 - 156 + a }$

$\sf{ b = 8 + a, d = 10 + a ...(3)}$

Subsitute (3) in ( 2 ) :-

$\sf{229+a = 161+8+a+c = 168+10+a+e}$

$\sf{ 229+a = 169+a+c = 178+a+e}$

We can write it as :-

$\sf{ 229+a = 169+a+c \:or\:229+a = 178+a+e}$

$\sf{ c = 299-169+a-a\:or\:e = 229-178+a-a}$

$\sf{ c = 60 \: and \: e = 51 }$

Subsitute the value of c and e in ( 1 ):-

$\sf{ 158 + b = 156 + d = 166 + a = 78 + 60 + 51 }$

$\sf{ 158 + b = 156 + d = 166 + a = 189}$

Now, 

$\sf{ For \: b, 158 + b = 189 }$

$\sf{ b = 189 - 158 }$

$\sf{ b = 31}$

$\sf{ For \: d , 156 + b = 189 }$

$\sf{ d = 189 - 156 }$

$\sf{ d = 33}$

$\sf{ For \: a, 166 + a = 189 }$

$\sf{ a = 189 - 166 }$

$\sf{ a = 23 }$

Hence, The value of a, b, c, d and e is 23, 31 ,60 ,33 and 51 .

8 0

3 years ago

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Answer:

Step-by-step explanation:

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Step-by-step explanation:

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Hopefully this help

Step-by-step explanation:

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3 years ago