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mezya [45]
3 years ago
12

Help me please. Best answer gets brainliest.

Mathematics
1 answer:
Lapatulllka [165]3 years ago
4 0

Answer:

3 for problem

Step-by-step explanation:

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A golf ball is hit with an initial velocity of 100 feet per second. The height of the golf ball can be represented by the equati
LenaWriter [7]

Answer:

  • 6.25 seconds

Step-by-step explanation:

<u>Using the the equation </u>

  • h = 100t − 16t^2

<u>The ball hits the ground, when h = 0, solving below equation:</u>

  • 100t − 16t^2 = 0
  • 4t(25 - 4t) = 0
  • t = 0 seconds, this is the starting point when ball was hit
  • 25 - 4t = 0 ⇒ 4t = 25 ⇒ t= 25/4 = 6.25 seconds later the ball hits the ground
5 0
3 years ago
Read 2 more answers
H(x) = −(x − 5)2 + 3
aleksandr82 [10.1K]
Max(f(x)) = f(3) = 4

Max(g(x)) = g(π/2) = 2

Max(h(x)) = h(5) = 3

Of these values, f(3) = 4 is the largest.


The function with the largest maximum is f(x).
8 0
3 years ago
Read 2 more answers
Order the following in ascending order. ​
fomenos
3/8 2/5 0.44 0.5 is the answer d !!
3 0
3 years ago
A jar contains four black buttons and five brown buttons. If five buttons are picked at random, what is the probability that at
lbvjy [14]

Answer:

189/572=33.042%

5 0
4 years ago
A brewery produces cans of beer that are supposed to contain exactly 12 ounces. But owing to the inevitable variation in the fil
MArishka [77]

Answer:

T \sim N (\mu = 6*12=72 , \sigma= \sqrt{6} *0.3=0.735)

P(T \leq 72) = P(Z< \frac{72-72}{0.735}) = P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solutio to the problem

Let X the random variable that represent the amount of beer in each can of a population, and for this case we know the distribution for X is given by:

X \sim N(12,0.3)  

Where \mu=12 and \sigma=0.3

For this case we select 6 cans and we are interested in the probability that the total would be less or equal than 72 ounces. So we need to find a distribution for the total.

The definition of sample mean is given by:

\bar X = \frac{\sum_{i=1}^n X_i}{n} = \frac{T}{n}

If we solve for the total T we got:

T= n \bar X

For this case then the expected value and variance are given by:

E(T) = n E(\bar X) =n \mu

Var(T) = n^2 Var(\bar X)= n^2 \frac{\sigma^2}{n}= n \sigma^2

And the deviation is just:

Sd(T) = \sqrt{n} \sigma

So then the distribution for the total would be also normal and given by:

T \sim N (\mu = 6*12=72 , \sigma= \sqrt{6} *0.3=0.735)

And we want this probability:

P(T\leq 72)

And we can use the z score formula given by:

z = \frac{x-\mu}{\sigma}

P(T \leq 72) = P(Z< \frac{72-72}{0.735}) = P(Z

6 0
3 years ago
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