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3 years ago

The half-life of a certain radioactive substance is 65 days. There are 3.5 g present initially.

Mathematics

1 answer:

zimovet [89]3 years ago

6 0

Answer:

r = 3.5 * .5^(t/65); around 117.5 days

Step-by-step explanation:

r = remaining substance

t = time in days

The half life is 65 day, meaning the .5 must be put to a power of t/65.

The initial substance was 3.5, which we must substitute in.

After using logarithms to solve our new equation, we are left with t=(about)117.5 days for there to be less than 1 gram of substance remaining.

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3 years ago

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sweet-ann [11.9K]

Given :

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To Find :

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Solution :

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3 years ago

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Gwar [14]

Answer:

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Step-by-step explanation:

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Check for extraneous solutions.

√(2(1) − 1) + 2 = 1

√(1) + 2 = 1

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No solution

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√(9) + 2 = 5

5 = 5

x = 5

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3 years ago

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Greeley [361]

(2,5) I think I’m sorry if I’m wrong:/

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3 years ago