Part (a)
The length is supposed to be 22.2 cm, but it could be 0.3 cm less
So 22.2 - 0.3 = 21.9 cm is the smallest value for the length. This is the lower bound of the length.
The upper bound is 22.2 + 0.3 = 22.5 cm as it is the largest the length can get.
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Use this for the width as well
The width is supposed to be 12 cm, but it could be as small as 12-0.3 = 11.7 cm and as large as 12+0.3 = 12.3 cm
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<h3>Answers:</h3>
- smallest length = 21.9 cm
- largest length = 22.5 cm
- smallest width = 11.7 cm
- largest width = 12.3 cm
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Part (b)
Use the smallest length and width to get the smallest possible area
smallest area = (smallest width)*(smallest length) = 11.7*21.9 = 256.23
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Repeat the same idea but for the largest length and width to get the largest possible area
largest area = (largest width)*(largest length) = 12.3*22.5 = 276.75
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<h3>
Answers:</h3>
- smallest area = 256.23 square cm
- largest area = 276.75 square cm
The answer to your problem is 2
Answer:
I think the answer is odd. I am not sure because I don't know this topic really well.
Step-by-step explanation:
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Match each equation with its solution set.
a2 − 9a + 14 = 0
a2 + 9a + 14 = 0
a2 + 3a − 10 = 0
a2 + 5a − 14 = 0
a2 − 5a − 14 = 0
It might be 0.133928571.....? I am unsure though. Sorry if this doesn't help
