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Vladimir [108]
2 years ago
9

Which function(s) are linear? Select all that apply.

Mathematics
1 answer:
Georgia [21]2 years ago
6 0

Answer:

3/5 x +1 and 7.5 x -7

Step-by-step explanation:

any equation in the form y= mx+b is linear the other 2 in this question are not in this form thus they are not linear

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Solve the equation <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%7D%20-6%2B2%3D6" id="TexFormula1" title=" \sqrt{x} -6+2=6" a
FromTheMoon [43]
Hope this helped you :)

4 0
4 years ago
Amplitude of y=-3sin5x
GaryK [48]

Answer:

Amplitude is 3

Step-by-step explanation:

in y=-3sin5x

the number in front of sign is always the amplitude. Its not negative 3 because the negative simply means it reflects across the x-axis

4 0
4 years ago
Read 2 more answers
Suppose the lengths of two sides of a right triangle are represented by 2x and 3 (x + 1), and the longest side is 17 units. Find
densk [106]

Answer:

x=4

Step-by-step explanation:

<u>Step 1</u>:-

given the lengths of two sides of a right angle are represented by 2x and 3(x+1) and longest side is 17 units.

AB = 2x and BC = 3(x+1) and longest side AC= 17

by using Pythagoras theorem

AC^2 = AB^2 + BC^2

<u>step 2:-</u>

The hypotenuse is longest side is AC = 17 units

(17)^2 = 4x^2 +9(X+1)^2

on simplification, we will use formula

(a + b)^2 = a^2 +2ab+b^2

289 = 4x^2 +9(x^2+2x+1)

13x^2 +18x-280 = 0

finding factors  70 X 52 = 3640

13x^2 +70x-52x-280 = 0

13x^2 -52x+ 70x-280 = 0

Taking common , we get

13x(x-4)+70(x-4)=0

x-4=0 and 13x+70=0

x=4 and 13x =-70

x=4 and x=\frac{-70}{13}

we can not choose negative value so x value is 4

Final answer:- x = 4

<u>verification:-</u>

<u></u>AC^2 = AB^2 + BC^2<u></u>

289 = 4(4)^2+9(4+1)^2

289 = 64 +9(25)

289=289

6 0
4 years ago
Read 2 more answers
What is the product?<br> 4927 x 7
Readme [11.4K]

Answer:

34489

Step-by-step explanation:

6 0
3 years ago
Can someone please help mee.<br><br> use transformations to solve the equation.<br><br> 3 2/3x = 22
gizmo_the_mogwai [7]

1. Note that

3\dfrac{2}{3}=\dfrac{3\cdot 3+2}{3}=\dfrac{9+2}{3}=\dfrac{11}{3}.

2. Then the equation 3\dfrac{2}{3}x=22 can be rewritten

\dfrac{11}{3}x=22.

3. Solve it:

x=22:\dfrac{11}{3},\\ \\x=22\cdot \dfrac{3}{11}=2\cdot 3=6.

Answer: x=6

7 0
3 years ago
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