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IRINA_888 [86]
3 years ago
15

Pls, help. ASAP. just think about the pts and brainliest

Mathematics
2 answers:
Alenkasestr [34]3 years ago
3 0

Answer:8.9

Step-by-step explanation:

192/43 is about 4.46

4.46*2 is about 8.9

Keith_Richards [23]3 years ago
3 0

8.9

192/43 is around 4.46

4.46*2 is around 8.9

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Alex makes $61,992 per year and pays about 25% of his gross monthly income in federal and state taxes. He wants to find an apart
ivanzaharov [21]

Answer:

Rent each month = $1421

Amount left after rent and taxes monthly = $2453

Step-by-step explanation:

Gross salary; $61,992 per year

His gross pay per month will be;

61992/12 = $5166

Now, the standard recommended rule in budgeting for house rent is to use between 25% to 30% of your monthly pay for rent.

Now, let's adopt an average of 27.5%

Thus;

Amount he can afford for rent each month = 27.5% × 5166 = $1420.65 ≈ $1421

We are told he pays 25% of his gross monthly income in federal and state taxes.

Thus, amount spent on taxes each month = 25% × 5166 = $1291.5 ≈ $1292

Thus, amount he will gave left after rent and taxes = 5166 - (1421 + 1292) = $2453

4 0
3 years ago
The length of a rectangle is 3 times the width. If the perimeter is to be greater than 56 meter. What are the lossible values fo
lidiya [134]

Answer:

w > 7

Step-by-step explanation:

L = 3w

2L + 2w > 56

sub for L

2(3w) + 2w > 56

6w + 2w > 56

8w > 56

w > 7


Check: L = 3(8)

L = 24

2(24) + 2(8) > 56

48 + 16 > 56

64 > 56

7 0
3 years ago
Read 2 more answers
3.01(the 1 is repeating)as a mixed number
Masteriza [31]
The quick and easy answer is 3/100
7 0
3 years ago
G<br> Express as a percent.<br> 4/5%
Aloiza [94]

Answer:

80%

Step-by-step explanation:

I'm assuming you meant express 4/5 as a percent and not 4/5%. So simply evaluate 4/5 to get 0.80. Now multiply this value by 100 to get the percentage which gives you 80%

5 0
2 years ago
The lifespan (in days) of the common housefly is best modeled using a normal curve having mean 22 days and standard deviation 5.
Natasha_Volkova [10]

Answer:

Yes, it would be unusual.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If Z \leq -2 or Z \geq 2, the outcome X is considered unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 22, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1

Would it be unusual for this sample mean to be less than 19 days?

We have to find Z when X = 19. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{19 - 22}{1}

Z = -3

Z = -3 \leq -2, so yes, the sample mean being less than 19 days would be considered an unusual outcome.

7 0
3 years ago
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