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olchik [2.2K]
4 years ago
5

Anfernee bought 4 umbrella and 5 hats and spent between $80.00 and 100.00. Each umbrella cost the same amount. Each hat cost the

same amount. The price of a hat is $4.00. What time s the least amount anfernee could have spent on an umbrella? What is the most anfernee most spent?
Mathematics
1 answer:
barxatty [35]4 years ago
6 0

Answer:

$15, $20

Step-by-step explanation:

Let u represent the unit price of umbrellas and h the unit price of hats.

Case 1:  A. spent $80.

Then $80 = 4u + 5($4), or $80 = $20 + 4u, or $60 = 4u, or

u = $15/umbrella.

Case 2:  A spent $100.

Then $100 = 4u + 5($4), or $100 = $20 + 4u, or $80 = 4u, or

u = $20/umbrella.

The least A. could have spent on a single umbrella was $15, and the most was $20.

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Answer is 125.
 Because it's cube root is an integer:)
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Which of the following statements is true?
Margaret [11]

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c

Step-by-step explanation:

it's more a gut feeling

5 0
4 years ago
The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 4. Suppose 64 golfers play
Vilka [71]

Answer:

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 75, \sigma = 4, n = 64, s = \frac{4}{\sqrt{64}} = 0.5

Find the probability that the average score of the 64 golfers exceeded 76.

This is 1 subtracted by the pvalue of Z when X = 64.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{76 - 75}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

6 0
4 years ago
68 increased by 75%
mash [69]

Let's see -

Follow the directions below to get your answer -

0.75 × 68 = 51

51 + 68 = 119

So, 119 is your answer

68 increased by 75% is 119.

↑   ↑   ↑  Hope this helps! :D


3 0
3 years ago
Read 2 more answers
16.
ss7ja [257]

The simplified polynomial that represents how many more economy cars are rented in w weeks than full-size cars is 53 - w.

<h3>Linear equation:</h3>

Linear equation is an equation in which the highest power of the variable is equals to one.

Therefore, the number of economy-size cars rented in w weeks is represented as follows:

  • 152 + 3w

The number of full-size cars rented in w weeks is represented as follows:

  • 99 + 2w

where

w = number of weeks

A  simplified polynomial that represents how many more economy cars are rented in w weeks than full-size cars is as follows:

  • 152 + 3w - (99 + 2w)
  • 152 + 3w - 99 - 2w
  • 53 - w

learn more on polynomial here: brainly.com/question/2566362

5 0
2 years ago
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