Answer:
Image 1
Step-by-step explanation:
To answer this question, we need to know how to use a box plot.
I've attached an image that demonstrates this well and can teach you what each part of the box plot means.
Specifically, the 2 farthest dots at the end are the minimum and maximum. The two sides where the box starts are the lower and upper quartiles. Finally, the line in the middle of the box is the median.
With this, we can analyze each box plot and determine which one is correct.
<em><u>Box Plot 1: </u></em><em>Everything is plotted correctly- Maximum and minimum plotted correctly, median plotted correctly, upper and lower quartile plotted correctly.</em>
<u>Box Plot 2:</u> Everything plotted correctly EXCEPT maximum of 48 is represented at 46.
<u>Box Plot 3:</u> Everything plotted correctly EXCEPT the upper quartile of 45 is at 39.
<u>Box Plot 4:</u> Upper quartile represented at 39 and maximum represented at 46 are both incorrect.
I'm not sure... I think it is 60 because 2*3=6 and 9*6=54 and when you add them together you get 60.
Answer:
<h2>(f + g)(x) = x² + 3x - 5</h2>
Step-by-step explanation:
we know that
For a polynomial, if
x=a is a zero of the function, then
(x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.
So
In this problem
If the cubic polynomial function has zeroes at 2, 3, and 5
then
the factors are
Part a) Can any of the roots have multiplicity?
The answer is No
If a cubic polynomial function has three different zeroes
then
the multiplicity of each factor is one
For instance, the cubic polynomial function has the zeroes
each occurring once.
Part b) How can you find a function that has these roots?
To find the cubic polynomial function multiply the factors and equate to zero
so
therefore
the answer Part b) is
the cubic polynomial function is equal to
Answer:
We know
sin (A + B) = sin A cos B + cos A sin B
sin (A - B) = sin A cos B - cos A sin B
(A + B) + sin (A - B)
= sin A cos B + cos A sin B + sin A cos B - cos A sin B
= sin A cos B + sin A cos B
= 2 sin A cos B
