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2 years ago

10

Why is my food yellow

2 answers:

Nataly_w [17]2 years ago

8 0

Answer:

bc I peed on it and bc of my stretchy cheese!!!!!!

Step-by-step explanation:

Fynjy0 [20]2 years ago

5 0

Answer:

well what are you eating?

Step-by-step explanation:

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Solve 7x − 2(x + 1) = 6x + 14. (5 points)<br><br> −12<br><br> 12<br><br> −16<br><br> 16

anygoal [31]

Answer:

C

X=-16

Step-by-step explanation:

5 0

3 years ago

1) Sandra saves 12% of her salary for retirement. This year her salary was $3000 more than in the previous year, and she saved $

svp [43]

Given:
savings 12% of her salary.
savings $4,200
This year's salary: x + 3,000
Last year's salary: x

4,200 represents 12% of her salary.
4,200 / 12% = 35,000 is her salary this year.

x + 3,000 = 35,000
x = 35,000 - 3,000
x = 32,000 her salary last year.

3 0

3 years ago

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Which expression is equivalent to 5(w+4) when w= 9?<br> 519)<br> 9(5)<br> 5(9)+4<br> O 5(9)+20

lana [24]

Answer:

D

Step-by-step explanation:

$5(9 + 4) \\ 5(13) \\ 65 \\ prove \: it \: d \: answer \\ 5(9) + 20 \\ 45 + 20 \\ = 65$

7 0

3 years ago

5 + 17 + 29 + 41 + 53<br><br><br><br> What is the 12th term of the series

Nezavi [6.7K]

The answer is 137 your welcome

7 0

2 years ago

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A random sample of math majors taking an introductory statistics course were surveyed after completing the final exam. They were

quester [9]

Answer:

$E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8$

Now we can find the second moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4$

The variance would be given by:

$Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96$

And the deviation would be:

$Sd(X) =\sqrt{6.96}= 2.638$

Step-by-step explanation:

For this case we have the following distribution given:

X 1 2 7

P(X) 1/5 2/5 2/5

We need to begin finding the mean with this formula:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8$

Now we can find the second moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4$

The variance would be given by:

$Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96$

And the deviation would be:

$Sd(X) =\sqrt{6.96}= 2.638$

7 0

3 years ago