<h3>
Answer: (-infinity, 7]</h3>
=====================================
Explanation:
The first interval (-infinity, 3) describes any number less than 3, so we can write x < 3 in short hand (where x is the unknown number).
The second interval (-1, 7] means we start at -1 and stop at 7. We do not include -1 but include 7. So we say that
(ie x is between -1 and 7; exclude -1, include 7)
If you were to graph each ona number line, you would see that the too intervals have overlapping parts. The right most edge extends out as far as x = 7. There is no left most edge as it goes onforever that direction.
Therefore, the to intervals combine to get
which turns into the interval notation answer of (-infinity, 7]
-----------
It might help to think of it like this: x < 3 and
say "x is some number that is less than 3, or it is between -1 and 7". So x could be anything less than 7, including 7 itself.
Given,
The line f and g are parallel lines.
a)The measure of angle 2 is 117 degree.
By exterior atlernate angle property,

The measure of angle 7 is 117 degree.
b)The measure of angle 4 is 68 degree.
By sum of adjacent angle between two parallel lines property,

The measure of angle 6 is 112 degree.
c)The measure of angle 5 is 32 degree.
By alternate interior angle property,

The measure of angle 4 is 32 degree.
d)The measure of angle 7 is 121 degree.
By corresponding angle property,

The measure of angle 3 is 121 degree.
Answer:
6.75 × 10^3
Step-by-step explanation:
Move the decimal 3 times to the left so that the resulting number, m = 6.75, is greater than or equal to 1 but less than 10
Since we moved the decimal to the left the exponent n is positive
n = 3
Write in the scientific notation form, m × 10^n
6.75 × 10^3
Answer:
5y - 6x = 8 or y = 6x/5 + 8/5
Step-by-step explanation:
let M1= gradient of line AB and M2= gradient of the second line
When two lines are perpendicular, the product of their gradients is -1
i.e, M1M2= -1
M2= -1/M1
A(2,9) and B(8,4)
gradient= (y2-y1)/(x2-x1)
M1= (4-9)/(8-2)
= -5/6
M2= -1÷ -5/6
-1 × -6/5= 6/5
Equation of the line passing through C(-3,-2)
[y-(-2)]/[x-(-3)= 6/5
(y+2)/(x+3)= 6/5
5(y+2)= 6(x+3)
5y+10=6x+18
5y= 6x + 8
y= 6x/5 + 8/5