Answer:
The slope of the line that contains diagonal OE will be = -3/2
Step-by-step explanation:
We know the slope-intercept form of the line equation
y = mx+b
Where m is the slope and b is the y-intercept
Given the equation of the line that contains diagonal HM is y = 2/3 x + 7
y = 2/3 x + 7
comparing the equation with the slope-intercept form of the line equation
y = mx+b
Thus, slope = m = 2/3
- We know that the diagonals are perpendicular bisectors of each other.
As we have to determine the slope of the line that contains diagonal OE.
As the slope of the line that contains diagonal HM = 2/3
We also know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line.
Therefore, the slope of the line that contains diagonal
OE will be = -1/m = -1/(2/3) = -3/2
Hence, the slope of the line that contains diagonal OE will be = -3/2
Answer:
g(q) = 5/8q
Step-by-step explanation:
-7q + 12r = 3q - 4r
Add 4r to each side
-7q + 12r+4r = 3q - 4r+4r
-7q +16r = 3q
Add 7q to each side
-7q+7q +16r = 3q+7q
16r = 10q
Divide each side by 16
16r/16 = 10q/16
r = 5q/8
g(q) = 5/8q
The answer is y=34
Explanation:
Answer:
an acute triangle
Explanation:
All of the angles are less than 90 degrees, which is an acute triangle.
Answer:
(2x-8)(2x+8)
4x squared -64 is the answer
how you get it is by multiplying 2x times 2x to get 4x squared and -8 times 8 = -64
hope this helps
if this is algebra 1 then this is right
