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telo118 [61]
3 years ago
6

Onbalance, the authors seem to _____________ (like or dislike) Roosevelt and his program. On p. 804, they say thatFDR was like _

____________________ in his espousal of big government, but like ____________________ in hisconcern for the common man.
Engineering
1 answer:
ehidna [41]3 years ago
5 0

Answer:

like; Hamilton; Jefferson.

Explanation:

In the given excerpt, there was a national depth expansion that was as a result of the war that occurred between 1939 and 1945. The war led to the destruction of basic amenities and infrastructures as well as buildings. This ultimately created national depth. It also cost a significant amount to rebuild from scratch.

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Air enters a compressor operating at steady state at 1.05 bar, 300 K, with a volumetric flow rate of "84" m3/min and exits at 12
Nina [5.8K]

Answer:

W = - 184.8 kW

Explanation:

Given data:

P_1 = 1.05 bar

T_1 = 300K

\dot V_1 = 84 m^3/min

P_2 = 12 bar

T_2 = 400 K

We know that work is done as

W = - [ Q + \dor m[h_2 - h_1]]

forP_1 = 1.05 bar,  T_1 = 300K

density of air is 1.22 kg/m^3 and h_1 = 300 kJ/kg

for P_2 = 12 bar, T_2 = 400 K

h_2 = 400 kj/kg

\dot m = \rho \times \dor v_1 = 1.22 \frac{84}{60} =1.708 kg/s

W = -[14 + 1.708[400-300]]

W = - 184.8 kW

8 0
3 years ago
Which of the following approaches to lean engineering consists of teams of people from different departments sharing
AURORKA [14]

Answer:

PDSA, where you work as a group

Explanation:

8 0
3 years ago
Question 8 of 10
Varvara68 [4.7K]
Gtfggyfbkuvjhkbghvfycuyivty
6 0
3 years ago
A steady, incompressible, two-dimensional velocity field is given by the following components in the x-y plane: u=1.85+2.05x+0.6
AnnZ [28]

Answer:

\frac{du}{dt} = 1.515

\frac{dv}{dt} = 5.511

Explanation:

The acceleration field is obtained by deriving the components in function of the time. That is to say:

\frac{du}{dt}=2.05\cdot \frac{dx}{dt}+0.656\cdot \frac{dy}{dt}\\\frac{dv}{dt} = -2.18\cdot \frac{dx}{dt} -2.05\cdot \frac{dy}{dt}

Where \frac{dx}{dt} = u and \frac{dy}{dt} = v.

The velocity components at given point are, respectively:

u = 2.424

v=-5.266

Lastly, the acceleration components are found:

\frac{du}{dt} = 1.515

\frac{dv}{dt} = 5.511

7 0
3 years ago
A civil engineer is performing a tensile test on a brick using a tension machine. Immediately after he adds the first weight, th
ki77a [65]
A high elastic modulus of brick
7 0
3 years ago
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