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Sedbober [7]
4 years ago
12

Which description defines the mechanical advantage of a simple lever?

Engineering
1 answer:
Artemon [7]4 years ago
3 0

The  mechanical advantage of a simple lever is C.  the ratio of the length of the effort arm to the length of the load arm

Explanation:

There are two types of mechanical advantage for a machine:

  • The Ideal Mechanical Advantage (IMA) is the mechanical advantage of the machine if there are no loss of energy due to internal frictions, i.e. if the output work is equal to the input work
  • The Actual Mechanical Advantage (AMA) is the real mechanical advantage of the machine, taking into account the energy lost due to internal frictional forces

The IMA of a lever can be calculated starting from the assumption that all the input work is transformed into output work with no loss of energy, therefore:

W_{in}=W_{out}\\F_{in} d_{in} = F_{out} d_{out}

where

F_{in},F_{out} are the effort and load forces, respectively

d_{in}, d_{out} are the effort and load arm, respectively

The mechanical advantage is a measure of the multiplication factor of the force, so we can write:

IMA=\frac{F_{out}}{F_{in}}=\frac{d_{in}}{d_{out}}

Therefore, the correct answer is

C.  the ratio of the length of the effort arm to the length of the load arm

Learn more about levers:

brainly.com/question/5352966

#LearnwithBrainly

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kogti [31]

Answer:

A. Flip-flops will never change state more than once per clock cycle, but latches can change state multiple times during a clock pulse.

Explanation:

Even though both flip-flops and latches are sequential circuits (which means that the present outputs don´t depend on the current value of the inputs and outputs but on the previous ones, so it is said that these circuits have memory), the flip-flops state changes are only valid when a clock pulse is present, which means that it can´t change state more than once per clock cycle .

Latches, instead, change state no sooner a input level changes, so it doesn´t need for a clock pulse to be present.

5 0
3 years ago
What is the standard half-cell potential for the oxidation of methane under acidic conditions? The reaction for methane is as fo
Yuri [45]

Answer:

The element that is oxidized is carbon.

Its oxidation state increased. It increased from -4 to +4

Explanation:

Oxidation is a process that involves increase in oxidation number.

The oxidation number of carbon in CH4 is -4

C + (1×4) = 0

C + 4 = 0

C = 0 - 4 = -4

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C + (2×-2) = 0

C - 4 = 0

C = 0+4 = 4

Increase in the oxidation number of carbon from -4 to +4 means carbon is oxidized

4 0
3 years ago
Two vertical parallel plates are spaced 0.01 ft apart. If the pressure decreases at a rate of 60 psf/ft in the vertical z-direct
Whitepunk [10]

Answer:

umax = 0.1259ft/s

Explanation:

Given:

•Distance between plates, B = 0.01ft

•Pressure difference decrease, \frac{dp}{dz}=60ps/ft

•Fluid viscosity, u = 10^-³lbf-s/ft²

Specific gravity, S = 0.80

Max velocity in the z-direction will be:

u_max= [\frac{B^2y}{8u}]\frac{dh}{ds}

But h = \frac{P}{y}+z

Substituting for h in the first equation, we have:

\frac{d}{dz}[\frac{p}{y}+z]

\frac{dh}{dz}=\frac{1}{y}\frac{dp}{ds}+\frac{dz}{dz}

= \frac{1}{0.8*62.4}(-60)+1

= -0.20192

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4 0
4 years ago
For this assignment, you will write a program to determine the time and date corresponding to an elapsed number of seconds since
Karolina [17]

A Python program should be written to produce output that corresponds to the given hour, minute, second, day of the month, month's name, year, and day of the week's name.

present_year=2016

present_month="January"

present_date="1"

present_day="Friday"

present_hour=0

present_minute=0

present_second=0

input<-from user(seconds)//taking imput from the user using Python program

   total_seconds=input

   //checking with seconds

   if(total_seconds<60)

       present_second+=total_seconds

   else

       total_minutes=total_seconds/60

       remaining_seconds=total_seconds-total_minutes*60

       present_second+=remaining_seconds

   //checking with minutes

   if(total_minutes<60)

       present_minute+=total_minutes

   else

       total_hours=total_minutes/60

       remaining_minutes=total_minutes-total_hours*60

       present_minute+=remaining_minutes

   //checklng with hours

   if(total_hours<24)

       present_hour+=total_hours

   else

       total_days=total_hours/24

       remaining_hours=total_hours-total_days*24

       present_hour+=remaining_hours

   //checking with days

   total_weeks=total_days/7

   remaining_day=total_days-total_weeks*7

   switch(remaining_day)

       case 1:

           present_day="Friday"

       case 2:

           present_day="Saturday"

       case 3:

           present_day="Sundayday"

       case 4:

           present_day="Monday"

       case 5:

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       case 6:

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       case 7:

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   //checking with years    

   if(total_days>366)

       while(total_days)

           if(present_year%4==0)

               total_days-=366

               present_year+=1

           if(present_year%4!=4)

               total_days-=365

               present_year+=1

           if(present_year%4!=0&&total_days<365)

               break;

           if(present_year%4==0&&total_days<366)

               break;

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   if(total_days<=366)

       while(total_days)

           if(present_month="January")

               present_date++

               total_days--

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                   present_month="April"

                   present_date=0        

           if(present_month="April")

               present_date++

               total_days--

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                   present_month="May"

                   present_date=0        

           if(present_month="May")

               present_date++

               total_days--

               if(present_date==31)

                   present_month="June"

                   present_date=0        

           if(present_month="June")

               present_date++

               total_days--

               if(present_date==30)

                   present_month="July"

                   present_date=0    

           if(present_month="July")

               present_date++

               total_days--

               if(present_date==31)

                   present_month="August"

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                   present_month="September"

                   present_date=0        

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               present_date++

               total_days--

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                   present_month="November"

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           if(present_month="November")

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//printing present time

print present_hour:present_minute:present_second present_date present_month present_year present_day          

Learn more about Python program here:

brainly.com/question/28691290

#SPJ4          

3 0
2 years ago
A divided multilane highway in a recreational area has four lanes (two lanes in each direction) and is on rolling terrain. The h
sertanlavr [38]

Answer:

Explanation:

Before: PT= 0.10, PB= 0.03 (given) ET = 2.5 ER = 2.0 (Table 6.5)

fHV= 0.847 (Eq. 6.5) PHF = 0.95, fp= 0.90, N=2, V = 2200 (given)

vp= V/[PHF⋅fHVTB⋅fp⋅N] = 1518.9 (Eq. 6.3)

BFFS = 50+5, BFFS =55 (given) fLW= 6.6

TLC=6+3=9 fLC= 0.65

fM= 0.0

fA= 1.0

FFS = BFFS −fLW−fLC–fM–fA= 46.75 (Eq. 6.7)

Use FFS=45 D= vp/S = 33.75pc/mi/ln Eq (6.6)

After: fA= 3.0

FFS = BFFS −fLW−fLC–fM–fA= 44.75 (Eq. 6.7)

Use FFS=45 Vnew= 2600 Vp= Va/[PHF⋅fHB⋅fp⋅N] = 1795 (Eq. 6.3) D= vp/S = 39.89pc/mi/ln

8 0
3 years ago
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