Answer:
a) Rmin ≈ 52 m
b) D = 110.184°
c) Lc ≈ 59 m
d) PT Station = 2827+12.37
PT Station = 2827+78.63
Explanation:
a) Given
v = 70 mph = (70 mph)(1,609 m/1 mile)(1 h/3600 s) = 31.286 m/s
e = 3% = 0.03
f = 0.12
a) We can use the equation
Rmin = v²/(127*(e + f))
⇒ Rmin = (31.286)²/(127*(0.03 + 0.12))
⇒ Rmin = 51.38 m ≈ 52 m
b) We can use the equation
D = 5729.578/R ⇒ D = 5729.578/52
⇒ D = 110.184°
c) We apply the formula
Lc = R*Δ/57.3
If Δ = 65° we have
Lc = 52*65/57.3
⇒ Lc = 58.98 m ≈ 59 m
d) If the PI is station 2827+45.50 we get the tangent length T as follows:
T = R*tan(Δ/2)
⇒ T = 52*tan(65/2) = 33.13 m
then, the station of the PC will be
PC Station = PI - T
⇒ PC Station = (2827+45.50) - (0+33.13) = 2827+12.37
and the station of the PT will be
PT Station = PI + T
⇒ PT Station = (2827+45.50) + (0+33.13) = 2827+78.63
Answer:
P= 541.5 kW.
Explanation:
Given that
velocity of water after leaving the nozzle ,v= 95 m/s
The mass flow rate of the water , m= 120 kg/s
The power generated P is given as

Now by putting the values in the above equation we get

P=541500 W
The power in kW will be 541.5 kW.
Therefore the answer will be 541.5 kW
P= 541.5 kW.
Answer:
Sealing agents are made of eco-friendly materials that are difficult to properly position in hard-to-reach places.
Explanation:
Answer:
Change in length = 0.1257 mm
Change in diameter= -0.03771mm
Explanation:
Given
Diameter, d = 15 mm
Length of rod, L = 200mm
F = Force= 300N
d = 0.015m
Ep=2.70 GPa, np=0.4.
First, we have to calculate the normal stress using
σ = F/A where F = Force acting on the Cross-sectional area
A = Area
Area is calculated as πd²/4 where d = 0.015m
A = 22/7 * 0.015²/4
A = 0.000176785714285m²
A = 1.768E-4m²
So, stress. σ = 300N/1.768E-4m²
σ = 1696832.579185520Pa
σ = 1.697MPa
Calculating E(long)
E(long) = σ /Ep
E(long) = 1.697E-3/2.70
E(long) = 0.0006285
At this point, we fan now calculate the change in length of the element;
∆L = E(long) * L
∆L = 0.0006285 * 200mm
∆L = 0.1257mm
Calculating E(lat)
E(lat) = -np * E(long)
E(lat) = -4 * 0.0006285
E(lat) = -0.002514
At this point, we can now calculate the change in diameter of the element;
∆D = E(lat) * D
∆L = -0.002514 * 15mm
∆L = -0.03771mm
Answer:
Yes the statement is true.
Explanation:
Power is defined as the rate at which energy is transferred by an object on account of work done.
Mathematically

An object that does work loses it's energy while an object on which work is done gains energy.
Power is often dependent on the type of energy transfer thus we have Electrical Power, Mechanical Power depending on the type of energy involved in the system.
Concept of power is important since it gives us a measure of how fast energy can be derived to given to a system.