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Sedbober [7]
4 years ago
12

Which description defines the mechanical advantage of a simple lever?

Engineering
1 answer:
Artemon [7]4 years ago
3 0

The  mechanical advantage of a simple lever is C.  the ratio of the length of the effort arm to the length of the load arm

Explanation:

There are two types of mechanical advantage for a machine:

  • The Ideal Mechanical Advantage (IMA) is the mechanical advantage of the machine if there are no loss of energy due to internal frictions, i.e. if the output work is equal to the input work
  • The Actual Mechanical Advantage (AMA) is the real mechanical advantage of the machine, taking into account the energy lost due to internal frictional forces

The IMA of a lever can be calculated starting from the assumption that all the input work is transformed into output work with no loss of energy, therefore:

W_{in}=W_{out}\\F_{in} d_{in} = F_{out} d_{out}

where

F_{in},F_{out} are the effort and load forces, respectively

d_{in}, d_{out} are the effort and load arm, respectively

The mechanical advantage is a measure of the multiplication factor of the force, so we can write:

IMA=\frac{F_{out}}{F_{in}}=\frac{d_{in}}{d_{out}}

Therefore, the correct answer is

C.  the ratio of the length of the effort arm to the length of the load arm

Learn more about levers:

brainly.com/question/5352966

#LearnwithBrainly

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Determine the minimum radius of a horizontal circular curve for a route having a 70 mph design speed, super-elevation (e) 3%, an
patriot [66]

Answer:

a) Rmin ≈ 52 m

b) D = 110.184°

c) Lc ≈ 59 m

d) PT Station = 2827+12.37

PT Station = 2827+78.63

Explanation:

a) Given

v = 70 mph = (70 mph)(1,609 m/1 mile)(1 h/3600 s) = 31.286 m/s

e = 3% = 0.03

f = 0.12

a) We can use the equation

Rmin = v²/(127*(e + f))

⇒ Rmin = (31.286)²/(127*(0.03 + 0.12))

⇒ Rmin = 51.38 m ≈ 52 m

b) We can use the equation

D = 5729.578/R  ⇒  D = 5729.578/52

⇒  D = 110.184°

c) We apply the formula

Lc = R*Δ/57.3

If  Δ = 65°  we have

Lc = 52*65/57.3

⇒ Lc = 58.98 m ≈ 59 m

d) If the PI is station 2827+45.50 we get the tangent length T as follows:

T = R*tan(Δ/2)

⇒ T = 52*tan(65/2) = 33.13 m

then, the station of the PC will be

PC Station = PI - T

⇒ PC Station = (2827+45.50) - (0+33.13) = 2827+12.37

and the station of the PT will be

PT Station = PI + T

⇒ PT Station = (2827+45.50) + (0+33.13) = 2827+78.63

3 0
4 years ago
A water jet that leaves a nozzle at 95 m/s at a flow rate of 120 kg/s is to be used to generate power by striking the buckets lo
Ksivusya [100]

Answer:

P= 541.5 kW.

Explanation:

Given that

velocity of water after leaving the nozzle ,v= 95 m/s

The mass flow rate of the water , m= 120 kg/s

The power generated P is given as

P=\dfrac{1}{2}mv^2

Now by putting the values in the above equation we get

P=\dfrac{1}{2}\times 120\times 95^2\ W

P=541500  W

The  power in kW will be 541.5 kW.

Therefore the answer will be 541.5 kW

P= 541.5 kW.

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3 years ago
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nydimaria [60]

Answer:

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4 0
4 years ago
Read 2 more answers
The acrylic plastic rod is 200 mm long and 15 mm in diameter. If an axial load of 300 N is applied to it, determine the change i
ehidna [41]

Answer:

Change in length = 0.1257 mm

Change in diameter= -0.03771mm

Explanation:

Given

Diameter, d = 15 mm

Length of rod, L = 200mm

F = Force= 300N

d = 0.015m

Ep=2.70 GPa, np=0.4.

First, we have to calculate the normal stress using

σ = F/A where F = Force acting on the Cross-sectional area

A = Area

Area is calculated as πd²/4 where d = 0.015m

A = 22/7 * 0.015²/4

A = 0.000176785714285m²

A = 1.768E-4m²

So, stress. σ = 300N/1.768E-4m²

σ = 1696832.579185520Pa

σ = 1.697MPa

Calculating E(long)

E(long) = σ /Ep

E(long) = 1.697E-3/2.70

E(long) = 0.0006285

At this point, we fan now calculate the change in length of the element;

∆L = E(long) * L

∆L = 0.0006285 * 200mm

∆L = 0.1257mm

Calculating E(lat)

E(lat) = -np * E(long)

E(lat) = -4 * 0.0006285

E(lat) = -0.002514

At this point, we can now calculate the change in diameter of the element;

∆D = E(lat) * D

∆L = -0.002514 * 15mm

∆L = -0.03771mm

8 0
3 years ago
The rate of energy transfer by work is called power. a)-True b)-False
Pie

Answer:

Yes the statement is true.

Explanation:

Power is defined as the rate at which energy is transferred by an object on account of work done.

Mathematically

Power=\frac{dE}{dt}

An object that does work loses it's energy while an object on which work is done gains energy.

Power is often dependent on the type of energy transfer thus we have Electrical Power, Mechanical Power depending on the type of energy involved in the system.

Concept of power is important since it gives us a measure of how fast energy can be derived to given to a system.

5 0
4 years ago
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