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Elis [28]
3 years ago
7

Here are the first four terms of a sequence.

Mathematics
1 answer:
Nataly_w [17]3 years ago
8 0

Answer:

  • aₙ = 2n² + n + 1

Step-by-step explanation:

We observe that the difference of terms is 4, 7 and 15 and next level difference is 4. It means the sequence is quadratic.

<u>We can compare this with simple quadratic sequence </u>

  • 1, 4, 9, 16

<u>and find out that doubling each term gives us </u>

  • 2, 8, 18, 32

This is close to our sequence, write the terms as follows to find exact rule

<u>The first term: </u>

  • a₁ = 4  = 2*1² + 2 = 2*1² + 1 + 1

<u>The second term</u>

  • a₂ = 11  = 2*2² + 3 = 2*2² + 2 + 1

<u>The third term:</u>

  • a₃ = 22 = 2*3² + 4 = 2*3² + 3 + 1

<u>The fourth term:</u>

  • a₄ = 37 = 2*4² + 5 = 2*4² + 4 + 1

<u>The nth term as per observation above is:</u>

  • aₙ = 2n² + n + 1
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Answer:

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Slope-intercept form of equation is given as $y=-2 x-2$.

Step-by-step explanation:

In the question, it is given that the slope of a line is -2 and it passes from (-2,2).

It is asked to write the point-slope form of the equation and rewrite it as slope-intercept form.

To do so, first find the values which are given in the question and put it in the formula of point-slope form. Simplify the equation to rewrite as slope-intercept form.

Step 1 of 2

Passing point of the line is (-2,2).

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$$y_{1}=2 \text {. }$$

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Substitute the above values in point-slope form of equation given by $y-y_{1}=m\left(x-x_{1}\right)$

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Hence, point-slope form of equation given as y-2=-2(x+2).

Step 2 of 2

Solve y-2=-2(x+2) to write it as slope-intercept form given by y=mx+c.

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Answer:

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Step-by-step explanation:

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