the circle has a diameter of 12, thus its radius is half that, or 6.
![\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=6 \end{cases}\implies A=\pi 6^2\implies A=36\pi \\\\\\ A \approx 113.0973355\implies A=\stackrel{\textit{rounded up}}{113.1}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D6%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%206%5E2%5Cimplies%20A%3D36%5Cpi%20%5C%5C%5C%5C%5C%5C%20A%20%5Capprox%20113.0973355%5Cimplies%20A%3D%5Cstackrel%7B%5Ctextit%7Brounded%20up%7D%7D%7B113.1%7D)
Answer:
C
Step-by-step explanation:
Using the tangent ratio in the right triangle
tanC = 
= 
= 
, then
C = 
( )
Without using a calculator I would say the root is between 10 and 11
How I found the answer:
I know 10 * 10 = 100
I know 11 * 11 = 121
So the root of 100 = 10 and the root of 121 = 11 so that means the root of 108 is somewhere between 10 and 11, which the root of 108 = 10.3923
Answer:
b = 32
Step-by-step explanation:
If we are talking a² + b² = c² instead of looking for the hypotenuse we look for a leg and it doesnt matter where it is placed.. so for there forth you'll do
24² + b² = 40²
and then from there you square all the numbers so then you get
576 + b² = 1600
then subtract 576 from both sides so you are left with
b² = 1024
and finally square root it
b = 32
So first convert to common denomenator( bottom number)
'
4 and 14
find least common multiple
factor
4=2 times 2
14=2 times 7
Least Common Multiple=2 times 2 times 7=28
1/4 times 7/7=7/28
8/14 times 2/2=16/28
add
5 1/4+8/14=5+1/4+8/14=5+7/28+16/28=5+23/28
the answer is 5 23/28
