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3 years ago

13

Okay, so lets say a teacher wants to divide her class of 30 students into 10 groups, but not necessarily of equal size. What are

some of her choices?

2 answers:

Phantasy [73]3 years ago

7 0

Well, she could do 30/10 which equals 3. So she could do 10 groups with 3 students in each group.

nata0808 [166]3 years ago

7 0

Simple, just pick a random number,like 2 or somthing.

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Answer:

$24,960

Step-by-step explanation:

1. Find daily salary (12*8 hours = 96/day)

2. find weekly salary (96*5 days = 480/week)

3. find annual salary (480*52 weeks = 24,960/year)

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3 years ago

8 is what percent of 64

Pavel [41]

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3 years ago

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3 years ago

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2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

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3 years ago

The height of a rocket a given number of seconds after it is released is modeled by h (t) = negative 16 t squared 32 t 10. What

V125BC [204]

The variable t represents the number of seconds that have passed after the release of the rocket.

<h3>Function</h3>

The function can be defined as an expression that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

The height of a rocket a given number of seconds after it is released is modeled by,

$h(t) = 6t^2 + 32t + 10$

As given in the above function, h (height) is the dependent variable which depends on the number of seconds t after the rocket is released (independent variable).

Hence we can conclude that the variable t represents the number of seconds after the rocket has been released.

To know more about the function, follow the link given below.

brainly.com/question/5245372.

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2 years ago