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valkas [14]
4 years ago
8

If point H is translated 6 units to the left and 5 units up, what are the coordinates of H'?

Mathematics
2 answers:
Hatshy [7]4 years ago
7 0

Answer:

if you can post a picture of the graph maybe I can tell you alright

Step-by-step explanation:

snow_tiger [21]4 years ago
7 0

Answer:

if i know the same graph its c -3,1

Step-by-step explanation: just took the test and got a 95

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Which graph represents y= ^3 square root of x +2?
yaroslaw [1]

Answer:

<h2>Hi there !</h2>

\huge\orange\star\:\huge\begin{gathered}{\underline{\boxed{\mathcal{\pink{Answer}}}}}\end{gathered}

y =  \sqrt[2]{x}+2 \: will \: pass \: through \: (0 \:, 2) \: and \: ( - 8 \:, 0)

Step-by-step explanation:

Hope it helps ya~

Stay safe, stay healthy and blessed

Have a good day!

Thank you

6 0
2 years ago
A cylindrical container has a radius of 3 centimeters and a height of 12 centimeters. The container is filled with water up to t
evablogger [386]

Answer:

volume of empty space = 141.3 cm³

Step-by-step explanation:

volume of empty space = volume of the cylinder - volume of water

First, we need to calculate the volume of the container

volume of a cylinder = πr²h

 where r = radius of the container   and   h is the height of the container

r = 3cm  and h = 12 cm    π is a constant which is ≈ 3.14

volume of a cylinder = πr²h

                                  =3.14 × 3²×12

                                   =3.14×9×12

                                    =339.12 cm³

We will proceed to find the volume of water

since liquid will take the shape of its container,

then volume of water =  πr²h

r is the radius of the container   and    h is the height of the water

r = 3cm    and   h = 7cm      

volume of water =  πr²h

                             = 3.14 ×3²×7

                              =3.14×9×7

                              =197.82 cm³

volume of empty space = volume of the cylinder - volume of water

                                          =339.12 cm³    -    197.82 cm³

                                          = 141.3 cm³

OR

WE CAN SOLVE DIRECTLY

height of empty space = height of container - height of water

                                       = 12 - 7

                                        =5 cm

volume of empty space = πr²h

                                        =3.14×3²×5

                                        =3.14×9×5

                                         =141.3 cm³

volume of empty space = 141.3 cm³

4 0
3 years ago
A company manufactures running shoes and basketball shoes. The total revenue (in thousands of dollars) from x1 units of running
Alborosie

Answer:

x_1 =2 , x_2=7

Step-by-step explanation:

Consider the revenue function given by R(x_1,x_2) = -5x_1^2-8x_2^2 -2x_1x_2+34x_1+116x_2. We want to find the values of each of the variables such that the gradient( i.e the first partial derivatives of the function) is 0. Then, we have the following (the explicit calculations of both derivatives are omitted).

\frac{dR}{dx_1} = -10x_1-2x_2+34 =0

\frac{dR}{dx_2} = -16x_2-2x_1+116 =0

From the first equation, we get, x_2 = \frac{-10x_1+34}{2}.If we replace that in the second equation, we get

-16\frac{-10x_1+34}{2} -2x_1+116=0= 80x_1-2x_1+116-272= 78x_1-156

From where we get that x_1 = \frac{156}{78}=2. If we replace that in the first equation, we get

x_2 = \frac{-10\cdot 2 +34}{2}=\frac{14}{2} = 7

So, the critical point is (x_1,x_2) = (2,7). We must check that it is a maximum. To do so, we will use the Hessian criteria. To do so, we must calculate the second derivatives and the crossed derivatives  and check if the criteria is fulfilled in order for it to be a maximum. We get that

\frac{d^2R}{dx_1dx_2}= -2 = \frac{d^2R}{dx_2dx_1}

\frac{d^2R}{dx_{1}^2}=-10, \frac{d^2R}{dx_{2}^2}=-16

We have the following matrix,  

\left[\begin{matrix} -10 & -2 \\ -2 & -16\end{matrix}\right].

Recall that the Hessian criteria says that, for the point to be a maximum, the determinant of the whole matrix should be positive and the element of the matrix that is in the upper left corner should be negative. Note that the determinant of the matrix is (-10)\cdot (-16) - (-2)(-2) = 156>0 and that -10<0. Hence, the criteria is fulfilled and the critical point is a maximum

8 0
3 years ago
Read 2 more answers
What dose this equal 2(6x-4)=3(6x+2)
AveGali [126]

Answer:

-7/3

Step-by-step explanation:

2(6−4)=3(6+2)

2(6x-4)=3(6x+2)

Solve

1

Distribute

2(6−4)=3(6+2)

{\color{#c92786}{2(6x-4)}}=3(6x+2)

12−8=3(6+2)

{\color{#c92786}{12x-8}}=3(6x+2)

2

Distribute

12−8=3(6+2)

12x-8={\color{#c92786}{3(6x+2)}}

12−8=18+6

12x-8={\color{#c92786}{18x+6}}

3

Add

8

8

to both sides of the equation

12−8=18+6

12x-8=18x+6

12−8+8=18+6+8

12x-8+{\color{#c92786}{8}}=18x+6+{\color{#c92786}{8}}

5 more steps

Solution

=−7/3

7 0
2 years ago
Read 2 more answers
Can some1 help with this please i am begging you
SSSSS [86.1K]

Answer:

it would be b

Step-by-step explanation:

8 0
3 years ago
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