Question

WILL GIVE BRAINLIEST AND 100 POINTS

Answer 1

Answer:

a) The interval for those who want to go out earlier is between 43.008 and 46.592

b) The interval for those who want to go out later is between 47.9232 and 51.9168

Step-by-step explanation:

Given that:

Sample size (n) =128,

Margin of error (e) = ±4% =

a) The probability of those who wanted to get out earlier (p) = 35% = 0.35

The mean of the distribution (μ) = np = 128 * 0.35 = 44.8

The margin of error = ± 4% of 448 = 0.04 × 44.8 =  ± 1.792

The interval = μ ± e = 44.8 ± 1.792 = (43.008, 46.592)

b) The probability of those who wanted to start school get out later (p) = 39% = 0.39

The mean of the distribution (μ) = np = 128 * 0.39 = 49.92

The margin of error = ± 4% of 448 = 0.04 × 49.92 =  ± 1.9968

The interval = μ ± e = 44.8 ± 1.792 = (47.9232, 51.9168)

The way for those who want to go out earlier to win if the vote is counted is if those who do not have any opinion vote that they want to go earlier