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Zielflug [23.3K]
4 years ago
5

_____ are lines that are neither parallel nor intersecting.

Mathematics
1 answer:
KonstantinChe [14]4 years ago
7 0

Answer: Skew line

Step-by-step explanation:

Because it’s 3 dimensional

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125% of x is 60. What is x
Lunna [17]

Answer:

Step-by-step explanation:

1.put your percent over a 100 so

125%/100 then put 60 over x

2.then cross multiply 100x60=6000

3.then divide 6000 by 125 which is percent

4.your answer is-48

8 0
3 years ago
Read 2 more answers
Solve the system using elimination and describe your steps. Be sure to verify your solution. • x = y - 3 2x + y = 12
hram777 [196]

So these are our two equations: 2x+y=12\\x=y-3

Before we can use elimination, subtract y on both sides of the first equation: 2x=-y+12\\x=y-3

Now we are able to use elimination. To eliminate the y variable, add the two equations together to get 3x=9 . From here we can solve for x.

For this, just divide both sides by 3 and your first answer will be x=3

Now that we have the value of x, substitute it into either equation to solve for y:

2*3+y=12\\6+y=12\\y=6\\\\3=y-3\\6=y

<u>In short, x = 3 and y = 6.</u>

6 0
4 years ago
The perimeter of a rectangle is 152m. If the length is one morethan twice of its width. Find the length and width of rectangle.​
sergejj [24]

Step-by-step explanation:

Perimeter of a Rect.= 2(l+b)

b= x

l= 2x

Equation

152= 2(2x+x)

152= 2(3x)

152= 6x

x= 25.33

2x= 50.66

Therefore length is 50.66m and breadth is 25.33m

3 0
3 years ago
How do I solve this?? Pls give details
vovikov84 [41]

Answer

45

Step-by-step explanation:

23+5x=14+25x

-25x

23-20x=14

+23

-20x=9

x=.45

45miles

7 0
3 years ago
Question 3 of 12
vichka [17]

Answer:

See explanation

Step-by-step explanation:

Given

Needed = 19000

Required

Support the jeweler's conclusion

From the question, we have that:

Boxes = 48

Bead = 400 per box

So, he bought a total of:

Total = 48 * 400

Total = 19200

<em>Since, he needed exactly 19000 and he has 192000, we can conclude that he has enough beads</em>

<em />

5 0
3 years ago
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