Answer:
e
f
∘
g
(
x
)
=
2
x
2
−
4
x
−
3
And
g
∘
f
(
x
)
=
(
2
x
−
3
)
(
2
x
−
5
)
Step-by-step explanation: f
(
x
)
=
2
x
−
3
g
(
x
)
=
x
2
−
2
x
=
f
(
g
(
x
)
)
=
f
(
x
2
−
2
x
)
=
2
(
x
2
−
2
x
)
−
3
=
2
x
2
−
4
x
−
3
g
∘
f
(
x
)
=
g
(
f
(
x
)
)
=
g
(
2
x
−
3
)
=
(
2
x
−
3
)
2
−
2
(
2
x
−
3
)
=
(
2
x
−
3
)
(
2
x
−
3
−
2
)
=
(
2
x
−
3
)
(
2
x
−
5
)
f
∘
g
(
x
)
≠
g
∘
f
(
x
)
Answer:
The probability that none of the 10 calls result in a reservation is 0.60%. In turn, the probability that at least one call results in a reservation being made is 99.40%.
Step-by-step explanation:
Since approximately 40% of the calls to an airline reservation phone line result in a reservation being made, supposing an operator handles 10 calls, to determine what is the probability that none of the 10 calls result in a reservation, and what is the probability that at least one call results in a reservation being made, the following calculations must be performed:
0.6 ^ 10 = X
0.006 = X
0.006 x 100 = 0.60%
Therefore, the probability that none of the 10 calls result in a reservation is 0.60%.
100 - 0.60 = 99.40
In turn, the probability that at least one call results in a reservation being made is 99.40%.
0.62068966 or 18/29 depending on how you want to set it up.
