Question

1 3/17 + 1 3/17 + 9/1720%20%2B%20%20%5Cfrac%7B9%7D%7B17%7D%20" id="TexFormula1" title="1 \frac{3}{17} + 1\frac{3}{17} + \frac{9}{17} " alt="1 \frac{3}{17} + 1\frac{3}{17} + \frac{9}{17} " align="absmiddle" class="latex-formula">

Answer 1

The first step to solving this is to convert the first mixed number into an improper fraction.
$\frac{20}{17}$ + 1$\frac{3}{17}$ + $\frac{9}{17}$
Now convert the second mixed number into an improper fraction
$\frac{20}{17}$ + $\frac{20}{17}$ + $\frac{9}{17}$
Since the denominator of each of these fractions are the same,, simply add each of the numerators of the fractions together in order to get your final answer.
$\frac{49}{17}$
This means that the correct answer to your expression is $\frac{49}{17}$,, or 2$\frac{15}{17}$ simplified.
Let me know if you have any further questions
:)

Answer 2

$1\frac{3}{17}+1\frac{3}{17}+\frac{9}{17}=\frac{20}{17}+\frac{20}{17}+\frac{9}{17}=\frac{49}{17}=2\frac{15}{17}\approx2.88235.$