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3 years ago

9

Two parallel lines, cut by transversal, are shown. One of the acute angles formed measures 80. Find the measures of all the othe

r angles

1 answer:

musickatia [10]3 years ago

4 0

The one across it is 100 and on both sides

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Put the equation in the correct order

alexgriva [62]

Distribute, 6x-21 +5 = -19, Combine like terms, 6x- 16=-19, add, 6x= -3, divide, x=-2

8 0

4 years ago

Algebra question! Help is much appreciated

UkoKoshka [18]

It’s y=3x+4.

The format for an equation like this is
Y=(slope)x+(y-int)

3 0

3 years ago

2. Which of the following equations are perpendicular to 2y = -3x + 1 I. II. III. y=-x-1 - 2x + 3y = -5 2x + 3y = 2 (A) I only (

Novay_Z [31]

The equation in given as ;

2y = -3x + 1

This can be written as ;

y= -3/2 x + 1/2

This means the equation has a gradient of -3/2

Let this slope , be , ---------m1

For perperdicular lines , the product of their slopes = -1 .This means if the other line has a gradient of m2 then : m1 * m2 = -1

So from the answers :

i) y= 2/3 x - 1 the slope is 2/3

m2 = 2/3

m1 * m2 = -1 -------check the if this is true by using the two values of gradient as;

-3/2 * 2/3 = - 1 ------ This is true-----equation i

II.

-2x + 3y = -5

3y = 2x -5

y= 2/3 x -5/3 -----m2 here is 2/3

m1*m2 = -1

-3/2 * 2/3 = -1 -----this is true , so ----equation ii

iii)

2x + 3y = 2

3y = -2x + 2

y= -2/3 x + 2/3 -----m2 = -2/3

m1*m2 = -1

-3/2 * -2/3 = 1 -----this is not true,,,equation iii is not perpendicular to our equation.

so, equation i and ii are perpendicular to our equation .

Answer : B i and ii only

4 0

1 year ago

In a sequence of ten terms, each term (starting with the third term) is equal to the sum of the two previous terms. The seventh

poizon [28]

Answer:

$\boxed{a_1+a_2+a_3+a_4+a_5+a_6+a_7+a_8+a_9+a_{10}=66}$

Step-by-step explanation:

We know that in a sequence of ten terms, each term (starting with the third term) is equal to the sum of the two previous terms. The seventh term is equal to 6. Therefore, we have

$a_1+a_2=x\\a_3=x\\a_4=2x\\a_5=3x\\a_6=5x\\a_7=8x\\$

We know that:

$a_7=6\\\implies 8x=6\\x=\frac{3}{4}$

We get:

$a_1+a_2=x=\frac{3}{4}\\\\a_3=x=\frac{3}{4}\\\\a_4=2x=\frac{3}{2}\\\\a_5=3x=\frac{9}{4}\\\\a_6=5x=\frac{15}{4}\\\\a_7=8x=6\\\\a_8=13x=\frac{39}{4}\\\\a_9=21x=\frac{63}{4}\\\\a_{10}=34x=\frac{102}{4}\\$

Therefore, we calculate

$\boxed{a_1+a_2+a_3+a_4+a_5+a_6+a_7+a_8+a_9+a_{10}=66}$

4 0

3 years ago

What is the length 52 ft the width is 9 ft

bogdanovich [222]

Assuming you're asking for the area and the length is 52 ft...

52 x 9 = 468

Area; 468 ft squared

3 0

3 years ago