All categories

3 years ago

Evaluate the function f(10) F(10)=6x^2-4x+25

Mathematics

1 answer:

Goryan [66]3 years ago

8 0

Answer:

Step-by-step explanation:

f(10) = 6(10)^2 - 4(10) + 25 = 6(100) - 40 + 25

600 - 40 + 25 = 520 + 25 = 545

You might be interested in

Help pls!! What is the segment of AC?

prohojiy [21]

Answer:

It's an angle bisector

Step-by-step explanation:

It is between 2 congruent angles therefore bisects those angles

4 0

2 years ago

Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1

belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

$F(x) = \int\limits^a_b {f(x)} \, dx$

By using integration formula

$\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c$

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

$\int\limits^6_^-6} (x^{5} + 8 x^{4} + 2 x^{2} + 5 x + 15) )dx$

<em>On integration , we get</em>

= $(\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}$

$F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)$

= $(\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))$

After simplification and cancellation we get

= $\frac{2 X 8 X (6)^{5} }{5} + \frac{2 X 2 X (6)^3}{3} + 2 X 15 X 6$

on calculation , we get

= $\frac{124,416}{5} + \frac{864}{3} + 180$

On L.C.M 15

= $\frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}$

= 25 351.2 units²

<u><em>Conclusion</em></u>:-

<em>The area of the region between the graph of the given function and the x-axis = 25,351 units²</em>

6 0

3 years ago

Use the rules for multiplication by powers of 10 to calculate 3 x 100

Yakvenalex [24]

300

because 3 x 1 = 3 +00 = 300... make sense?

4 0

3 years ago

A person is on the outer edge of a carousel with a radius of 20 feet that is rotating counterclockwise around a point that is ce

lubasha [3.4K]

<h2>Answer:</h2>

$\boxed{(5(-\sqrt{2}+\sqrt{6}),5(\sqrt{2}+\sqrt{6}))}$

<h2>Step-by-step explanation:</h2>

The origin of the coordinate system is the center of the circle. So we have an angle that measures $5\pi/12=75^{\circ}$ . so the x-coordinate and y-coordinate can be found, by using trigonometry as follows:

$x=20cos(5\pi/12)=5\sqrt{6}-5\sqrt{2} \\ \\ Arranging:\\ \\x=5(-\sqrt{2}+\sqrt{6}) \\ \\y=20sin(5\pi/12)=5\sqrt(6)+5\sqrt{2} \\ \\ Arranging:\\ \\y=5(\sqrt{2}+\sqrt{6})$

Finally, the exact value of the position of the rider after the carousel rotates $5\pi/12$ radians is:

$\boxed{(5(-\sqrt{2}+\sqrt{6}),5(\sqrt{2}+\sqrt{6}))}$

3 0

3 years ago

The total cost for 8 bracelets, including shipping was $54. The shipping charge was $6. Define your variable and write an equati

Alenkasestr [34]

8x+6=54
    -6   -6
    8x=48
8x /8=48/8
      x=6 the bracelets were $6 a piece

5 0

4 years ago

Read 2 more answers