7/3x+1/3x=3x+6/3+5/3x
8/3x-5/3x=3x+6/3
3/3x=3x+6/3
x=3x+6/3
x-3x=6/3
-2x=2
-x=2/2
-x=1
x=-1
The correct numbers to use in solving problems about
spans of time like B.C. and A.D. should be “integers”.
Integers are whole numbers (not a fractional number or not a decimal
number) which can take a value of negative, zero, or positive number. Example
of integers would be -1, 0 and 1.
<span>In calculations, the time period would be on the x-axis. Since
B.C. and A.D. are two different spans of time, therefore in the calculations,
the date of BC should be negative (negative x-axis) while the date of AD should
be positive (positive x-axis). This would place the origin as the common
reference.</span>
<span>a) Differentiate both sides of lnq − 3lnp + 0.003p=7 with respect to p, keeping in mind that q is a function of p and so using the Chain Rule to differentiate any functions of q:
(1/q)(dq/dp) − 3/p + 0.003 = 0
dq/dp = (3/p − 0.003)q.
So E(p) = dq/dp (p/q) = (3/p − 0.003)(q)(p/q) = (3/p − 0.003)p = 3 − 0.003p.
b) The revenue is pq.
Note that (d/dp) of pq = q + p dq/dp = q[1 + dq/dp (p/q)] = q(1 + E(p)), which is zero when E(p) = −1. Therefore, to maximize revenue, set E(p) = −1:
3 − 0.003p = −1
0.003p = 4
p = 4/0.003 = 4000/3 = 1333.33</span>
Answer:
Cos^2x csc^2x
Step-by-step explanation:
Cos^2x (1 + cot^2x)
Answer:
39°
Step-by-step explanation:
IM assuming xyz is a triangle
180 - 113 - 28 = 67 - 28 = 39
