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PolarNik [594]
2 years ago
7

Help pls!! What is the segment of AC?

Mathematics
1 answer:
prohojiy [21]2 years ago
4 0

Answer:

It's an angle bisector

Step-by-step explanation:

It is between 2 congruent angles therefore bisects those angles

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Triangle WYT is an isosceles if angle Y is equal to 156 then what are the other two angles? brainliest and five⭐ for the first w
Monica [59]

Answer: 12

Step-by-step explanation:

since it’s isosceles, the bottom two angles are equal so just subtract 156 from 180 and then divide that by 2.

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2 years ago
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A peach orchard owner wants to maximize the amount of peaches produced by her orchard.
qaws [65]

Answer:

  a) Y(x) = {900, x≤30; 900-40(x-30), x>30}

  b) T(x) = {900x, x≤30; 2100x-40x², x>30}

  c) dT/dx = {900, x≤30; 2100-80x, x>30}

Step-by-step explanation:

a) The problem statement gives the function for x ≤ 30, and gives an example of evaluating the function for x = 35. So, replacing 35 in the example with x gives the function definition for x > 30.

\displaystyle Y(x)=\left\{\begin{array}{lcl}900&\text{for}&x\le 30\\900-40(x-30)&\text{for}&x>30\end{array}\right.

__

b) The yield per acre is the product of the number of trees and the yield per tree:

  T(x) = x·Y(x)

\displaystyle T(x)=\left \{\begin{array}{lcl}900x&\text{for}&x\le 30\\2100x-40x^2& \text{for}&x>30\end{array}\right.

__

c) The derivative is ...

\displaystyle\frac{dT}{dx}=\left \{\begin{array}{lcl}900&\text{for}&x\le 30\\2100-80x& \text{for}&x>30\end{array}\right.

_____

The attached graph shows the yield per acre (purple, overlaid by red for x<30), the total yield (black), and the derivative of the total yield (red). You will note the discontinuity in the derivative at x=30, where adding one more tree per acre suddenly makes the rate of change of yield be negative.

6 0
3 years ago
Devon invests $9,000 in a savings account that pays 1.5% simple interest. How much will be in the account after 6 years if Devon
MAVERICK [17]
$810 because if you use the simple interest formula (s=p*r*t), you get $810 hope this helped!
4 0
3 years ago
If both diagonals of a quadrilateral bisect each other when is the quadrilateral a parallelogram?
slamgirl [31]
It is more than just a quadrilateral. In fact it is going to be hard to pick.

These facts suit a square,  a rectangle, a rhombus, and a parallelogram. And the above statement is true, but maybe a little harder to prove than the converse of the statement, which is the usual one you find.

The converse is "If you have a parallelagram, the diagonals bisect each other."

You might think a trapezoid deserves some mention. The diagonals of a trapezoid do not bisect each other.
6 0
3 years ago
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